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Error mitigation can improve an expectation estimate while making its statistical uncertainty or calibration sensitivity much larger. Sometimes the available noisy data contain no information about the desired quantity at all. Understanding these limits helps distinguish a useful finite calculation from a promise of efficient recovery for arbitrary circuits.

The central questions are concrete: which ideal quantity is required, which noisy experiments are available, what error is acceptable, and how much total work can be spent? A lower bound answers these questions for a specified class of problems. It need not rule out a simpler observable, a restricted state family or a useful calculation at modest size.

Required background. Error mitigation introduces the main estimators and their costs. Lower bounds and limitations explains worst-case statements and resource assumptions.

Helpful background. Measurement as estimation develops risk and confidence; algorithmic benchmarking compares complete tasks at matched resources.

Usually the target is μ=Tr⁡(Oρid)\mu=\operatorname{Tr}(O\rho_{\rm id}), with a bounded observable normalized so that −1≤O≤1-1\leq O\leq1. Returning an accurate number does not necessarily prepare a corrected state. Signed estimates for different observables may not even agree with one physical density operator.

Producing samples from a nearly ideal distribution is a different task. A few moments need not determine that distribution: two-bit strings uniformly distributed over {00,11}\{00,11\} or over {01,10}\{01,10\} have identical single-bit marginals but opposite parity. Neither a few expectations nor classical samples supply a coherent quantum state for later gates. Quek et al. (2024) distinguish expectation estimation from distribution sampling and study the gap between them.

Specify the available information too. Noisy measurement records, joint access to several output states, deliberately modified circuits, calibration data and a classical description of the input are different resources. If the ideal answer can be computed classically, a protocol may need no quantum samples while still using substantial classical work. A sample bound alone cannot exclude that option.

Physical channels contract trace distance:

D(ρ,σ)=12∥ρ−σ∥1,D(N(ρ),N(σ))≤D(ρ,σ).\begin{aligned} D(\rho,\sigma)&=\tfrac12\lVert\rho-\sigma\rVert_1,\\ D(\mathcal N(\rho),\mathcal N(\sigma))&\leq D(\rho,\sigma). \end{aligned}

If two possible ideal states have well-separated target expectations but nearly identical noisy outputs, any estimator accurate on both could also distinguish those outputs. This connects mitigation to statistical discrimination. The number of copies and their joint distinguishability, not just single-copy contraction, determine a quantitative sampling bound; Takagi et al. (2022) develop this approach.

Complete dephasing gives a particularly sharp example:

D(ρ)=12(ρ+ZρZ).\mathcal D(\rho)=\tfrac12(\rho+Z\rho Z).

Both ∣+⟩|+\rangle and ∣−⟩|-\rangle become I/2I/2, but their ideal XX expectations are +1+1 and −1-1. Suppose the input label is unknown and the procedure receives only these dephased outputs. Every possible observation has the same distribution in the two cases. No number of copies can identify which XX expectation was present.

This does not make every observable unrecoverable. The same channel preserves Tr⁡(Zρ)\operatorname{Tr}(Z\rho) exactly. What matters is whether the desired quantity is constant across states that produce identical available data. Extra preparation information, a restricted input family or a new experiment can change that question.

Let independent observed values Xi=±1X_i=\pm1 have distribution

Pr⁡(Xi=x)=1+xημ2,\Pr(X_i=x)=\frac{1+x\eta\mu}{2},

where μ∈[−1,1]\mu\in[-1,1] is unknown and the attenuation 0<η≤10<\eta\leq1 is known. The observed mean is ημ\eta\mu. Dividing the sample mean by η\eta gives

μ^=X‾/η,Eμ^=μ,Var⁡(μ^)=1−η2μ2Nη2.\begin{aligned} \widehat\mu&=\overline X/\eta,\\ \mathbb E\widehat\mu&=\mu,\\ \operatorname{Var}(\widehat\mu)&=\frac{1-\eta^2\mu^2}{N\eta^2}. \end{aligned}

There is a precise lower-bound interpretation here. The single-record Fisher information is

I(μ)=∑x=±1px(∂μlog⁡px)2=η21−η2μ2.\begin{aligned} I(\mu)&=\sum_{x=\pm1}p_x(\partial_\mu\log p_x)^2\\ &=\frac{\eta^2}{1-\eta^2\mu^2}. \end{aligned}

For regular unbiased estimation at interior parameter values, the Cramér–Rao bound is Var⁡μ^≥1/[NI(μ)]\operatorname{Var}\widehat\mu\geq1/[NI(\mu)]. The rescaled mean attains it. Thus its large variance is not merely a poor choice among unbiased estimators for this binary experiment. It is not a bound for every possible mitigation experiment.

As a physical realization, apply a qubit depolarizing channel with Bloch contraction 1−p1-p repeatedly to an unknown state and finally measure ZZ. With no intervening dynamics changing the target component, LL repetitions give η=(1−p)L\eta=(1-p)^L. At p=.02,L=100p=.02,L=100, η≃.1326\eta\simeq.1326 and η−2≃56.86\eta^{-2}\simeq56.86. At μ=0\mu=0, a standard error at most .01.01 requires N≥568572N\geq568572. This is a variance requirement, not a high-probability confidence guarantee or a formula for arbitrary layered circuits.

Calibration error survives infinite science shots

Section titled “Calibration error survives infinite science shots”

If the actual attenuation is η\eta but the analysis uses η~\widetilde\eta, then

Eμ^−μ=μ(η/η~−1).\mathbb E\widehat\mu-\mu=\mu(\eta/\widetilde\eta-1).

For η=.2\eta=.2, η~=.21\widetilde\eta=.21 and μ=.6\mu=.6, the bias is about −.0286-.0286, however many science records are collected. If an independent attenuation calibration has small variance vηv_\eta, first-order propagation adds approximately μ2vη/η2\mu^2v_\eta/\eta^2 to the science variance. Near zero attenuation the linear approximation can fail, so use an uncertainty model that respects the full denominator distribution.

An estimator’s mean-squared error is its squared bias plus its variance. Exact inversion removes the attenuation bias under a correct model, but it may be a poor choice at a fixed sample budget. Consider the shrinkage family

μ^λ=λX‾/η,0≤λ≤1.\widehat\mu_\lambda=\lambda\overline X/\eta,\qquad0\leq\lambda\leq1.

Its risk at the true μ\mu is

V=1−η2μ2Nη2,MSE⁡(μ^λ)=(1−λ)2μ2+λ2V.\begin{aligned} V&=\frac{1-\eta^2\mu^2}{N\eta^2},\\ \operatorname{MSE}(\widehat\mu_\lambda) &=(1-\lambda)^2\mu^2+\lambda^2V. \end{aligned}

The uncorrected mean corresponds to λ=η\lambda=\eta and exact inversion to λ=1\lambda=1. For η=.2\eta=.2, μ=.6\mu=.6, N=100N=100, their risks are about .2403.2403 and .2464.2464. Intermediate shrinkage can do better:

Squared bias falls and variance rises with correction strength; their sum has a minimum before exact inversion

Exact finite-binomial risk for the specified state and sample count. The minimum lies near λ=.594\lambda=.594, with MSE about .1463.1463. This is a pointwise comparison using the true expectation for analysis; the location of that minimum is not available to an estimator that does not know μ\mu.

The pointwise optimum λ⋆=μ2/(μ2+V)\lambda_\star=\mu^2/(\mu^2+V) depends on the unknown answer. Practical regularization therefore needs a stated prior, a worst-case criterion or separate training data, followed by an honest assessment of transfer. Choosing the best correction after looking at the final reference answer does not demonstrate a predictive method. Data-driven mitigation explicitly raises this training-distribution question (Lowe et al., 2021).

Clipping an estimate to [−1,1][-1,1] cannot increase its squared error for a target in that interval: projection onto the interval moves every out-of-range value closer to every allowed target. It can introduce bias, and it does not automatically preserve an interval’s confidence coverage. Regularization changes the estimator class, so it does not contradict a theorem restricted to unbiased estimators.

Distinguish necessary and sufficient sample counts

Section titled “Distinguish necessary and sufficient sample counts”

For a fixed unbiased estimator expressed as an average of independent Zi∈[−Γ,Γ]Z_i\in[-\Gamma,\Gamma], Hoeffding’s inequality gives the sufficient choice

N≥2Γ2ϵ2log⁡2δN\geq\frac{2\Gamma^2}{\epsilon^2}\log\frac2\delta

for error at most ϵ\epsilon except with probability δ\delta. At Γ=2,ϵ=.02,δ=.05\Gamma=2,\epsilon=.02,\delta=.05, this gives 7377873778 records. It is conservative and is not a lower bound on all estimators. With a known bias bound B<ϵB<\epsilon, use ϵ−B\epsilon-B for the deviation about the estimator’s mean; uncertain calibration needs its own probability statement.

Signed combinations also depend on allocation. With independent strata, weights (1.5,−.5)(1.5,-.5), unit per-shot variance and 2000020000 total shots:

Allocation Shots in the two strata Variance
Equal (10000,10000)(10000,10000) .00025.00025
Minimum variance (15000,5000)(15000,5000) .00020.00020

The optimum follows from nj∝∣wj∣σjn_j\propto|w_j|\sigma_j. Shared calibration or measurement records create covariance, so the independent-stratum formula then needs modification. See probabilistic cancellation and extrapolation for their specific sampling designs.

Read a circuit-level lower bound with its assumptions

Section titled “Read a circuit-level lower bound with its assumptions”

Takagi, Tajima and Gu (2023), Theorem 3, consider MM qubits with local depolarization of strength at least γ\gamma on every qubit after each of LL selected unitary layers. Intermediate operations are unital maps on those same MM qubits; a final arbitrary joint process receives NN distorted output states. This excludes encoded error correction from that circuit model.

Require absolute estimation error at most δ\delta with probability at least 1−ε1-\varepsilon for every target state and observable. If two target expectations differ by more than 2δ2\delta, their bound implies

N≥(1−2ε)22ln⁡(2) M(1−γ)2L.N\geq\frac{(1-2\varepsilon)^2}{2\ln(2)\,M(1-\gamma)^{2L}}.

For M=4,L=200,γ=.02,ε=.05M=4,L=200,\gamma=.02,\varepsilon=.05, the right side is about 472.21472.21, requiring at least 473473 output states. For example, ∣0000⟩,∣1111⟩|0000\rangle,|1111\rangle and observable ∣0000⟩⟨0000∣|0000\rangle\langle0000| are separated by one, so δ=.2\delta=.2 meets the separation condition. The count is necessary, not sufficient; it excludes calibration costs and elapsed time.

The exponential dependence is on the selected noisy depth under these hypotheses. It is not a measured cost prediction for every device. Other results use different estimator classes: Tsubouchi, Sagawa and Yoshioka (2023) obtain quantum-estimation bounds for unbiased observable estimation in their virtual-circuit model, including depth scaling and width scaling for specified random-circuit ensembles. Those are distinct statements.

Quek et al. (2024) construct worst-case rapidly mixing circuit families with much stronger sampling barriers, allowing collective output measurements. Input-state knowledge matters: their input-aware result admits a classical-computation alternative. Their shortest-depth constructions and geometrically local variants have different connectivity assumptions. A particular finite experiment must match the relevant model before a bound can be applied.

These theorems constrain uniform promises over a family. A local observable with a small relevant region, a shallow circuit, or a restricted input family may remain tractable. Conversely, a few successful sizes do not determine the asymptotic scaling law. An expectation estimate does not establish accurate distribution sampling, state recovery or fault-tolerant computation.

Count calibration, circuit selection, modified runs, rejected outcomes and reference calculations along with science shots. Reusing calibration across many circuits can reduce its cost per answer, but only over a range where that calibration remains applicable. Test the combined estimator when methods share records or change the physical circuits; component variances and improvements do not simply add.

For independent acceptance probability .18.18, collecting 50005000 retained records needs 5000/.18≃277785000/.18\simeq27778 attempts on average. Adding 60006000 calibration attempts and taking 1.4 ms1.4\,\mathrm{ms} per attempt gives expected time about 47.29 s47.29\,\mathrm{s}. A fixed budget near that mean does not guarantee 50005000 successes; a high-confidence budget requires a tail calculation. If the accepted mean is .72.72, the unnormalized moment is .1296.1296. Neither equals the original ideal target without a physical argument; see symmetry verification.

Choose accuracy, confidence and cost measures that match the application. Compare with the raw estimator and an appropriate classical method on fresh tasks, including failures and uncertain reference values. If an unstable direction dominates, reducing correction strength or changing the experiment may help. If the application needs a long-lived unknown quantum state, estimation of a few final observables cannot supply it; quantum error correction addresses a different requirement.

For the dephased ∣+⟩,∣−⟩|+\rangle,|-\rangle example, show that every estimator has worst-case MSE at least one when it has no input label or other distinguishing information.

Solution

Its output WW has the same distribution under both inputs. Averaging the two risks gives 12E[(W−1)2+(W+1)2]=E[W2]+1≥1\tfrac12\mathbb E[(W-1)^2+(W+1)^2]=\mathbb E[W^2]+1\geq1. At least one risk is therefore at least one. Returning zero attains this minimax value. Additional copies remain identically distributed, so they cannot lower it.

Compute the score of px=(1+xημ)/2p_x=(1+x\eta\mu)/2 and show that the rescaled mean attains the unbiased variance bound.

Solution

The score is xη/(1+xημ)x\eta/(1+x\eta\mu). Averaging its square gives I=η2/(1−η2μ2)I=\eta^2/(1-\eta^2\mu^2). Since Var⁡(X)=1−η2μ2\operatorname{Var}(X)=1-\eta^2\mu^2, the estimator X‾/η\overline X/\eta has variance 1/(NI)1/(NI). This uses known attenuation, independent records and interior parameters; it does not prohibit lower pointwise MSE with bias.

Differentiate the plotted risk and explain why its minimizer is not immediately an implementable prescription.

Solution

Setting −2(1−λ)μ2+2λV=0-2(1-\lambda)\mu^2+2\lambda V=0 gives λ⋆=μ2/(μ2+V)\lambda_\star=\mu^2/(\mu^2+V). Here V=.2464V=.2464, hence λ⋆≃.5937\lambda_\star\simeq.5937 and minimum risk μ2V/(μ2+V)≃.1463\mu^2V/(\mu^2+V)\simeq.1463. Both depend on the unknown μ\mu. An estimator needs a choice based on permitted information and a new risk analysis for any data-dependent tuning.

Prove that clipping to [−1,1][-1,1] cannot increase squared error for μ∈[−1,1]\mu\in[-1,1]. Does this imply unbiasedness?

Solution

Values already inside the interval do not change. If W>1W>1, then 0≤1−μ≤W−μ0\leq1-\mu\leq W-\mu; if W<−1W<-1, the analogous inequality holds at −1-1. Squaring proves the pointwise result and averaging proves the MSE result. The clipping transformation is nonlinear and need not preserve the estimator’s expectation.

5. Separate three meanings of a sample count

Section titled “5. Separate three meanings of a sample count”

Classify the counts 568572568572, 7377873778 and 473473 above.

Solution

The first meets a specified standard error in an exactly solved binary attenuation model at μ=0\mu=0. The second is a sufficient concentration bound for independent bounded unbiased outputs. The third is a necessary circuit-model lower bound. They address different models and accuracy criteria, so their numerical ordering is not a comparison of competing protocols.

6. Distinguish expected and reliable acceptance budgets

Section titled “6. Distinguish expected and reliable acceptance budgets”

Let each independent attempt succeed with probability aa. Give the mean and variance of the attempt count needed for mm successes, and a fixed-budget expression for the chance of obtaining fewer than mm.

Solution

The stopping count is a sum of mm independent geometric waiting times:

ET=m/a,Var⁡(T)=m(1−a)/a2.\begin{aligned} \mathbb E T&=m/a,\\ \operatorname{Var}(T)&=m(1-a)/a^2. \end{aligned}

With a fixed NN attempts, the failure probability is ∑k=0m−1(Nk)ak(1−a)N−k\sum_{k=0}^{m-1}\binom Nk a^k(1-a)^{N-k}. The expectation m/am/a is not a high-confidence budget. For a=.18,m=5000a=.18,m=5000, the stopping-time standard deviation is about 356356 attempts.

  • A. Lowe, M. H. Gordon, P. Czarnik, A. Arrasmith, P. J. Coles, and L. Cincio, “Unified Approach to Data-Driven Quantum Error Mitigation,” Physical Review Research 3, 033098 (2021), doi:10.1103/PhysRevResearch.3.033098.
  • Y. Quek, D. Stilck França, S. Khatri, J. J. Meyer, and J. Eisert, “Exponentially Tighter Bounds on Limitations of Quantum Error Mitigation,” Nature Physics 20, 1648–1658 (2024), doi:10.1038/s41567-024-02536-7.
  • R. Takagi, S. Endo, S. Minagawa, and M. Gu, “Fundamental Limits of Quantum Error Mitigation,” npj Quantum Information 8, 114 (2022), doi:10.1038/s41534-022-00618-z.
  • R. Takagi, H. Tajima, and M. Gu, “Universal Sampling Lower Bounds for Quantum Error Mitigation,” Physical Review Letters 131, 210602 (2023), doi:10.1103/PhysRevLett.131.210602.
  • K. Tsubouchi, T. Sagawa, and N. Yoshioka, “Universal Cost Bound of Quantum Error Mitigation Based on Quantum Estimation Theory,” Physical Review Letters 131, 210601 (2023), doi:10.1103/PhysRevLett.131.210601.