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Three-Dimensional Wave Mechanics

In three dimensions, a wavefunction assigns an amplitude to every point in space. The main new choices are geometric: which coordinates fit the potential, which boundary conditions describe the container, and which measure converts a density into probability? This chapter develops these choices through boxes, free particles, and spherical separation.

For a spinless particle with a scalar potential,

H=−ℏ22m∇2+V(r),∫∣ψ(r)∣2 d3r=1.H=-\frac{\hbar^2}{2m}\nabla^2+V(\mathbf r), \qquad \int |\psi(\mathbf r)|^2\,d^3r=1.

Changing coordinates does not change the state, but it changes how derivatives and volume elements are written. In spherical coordinates,

d3r=r2sin⁡θ dr dθ dϕ.d^3r=r^2\sin\theta\,dr\,d\theta\,d\phi.

Consequently, equal intervals in rr, θ\theta, and ϕ\phi do not describe equal volumes. The Jacobian is part of the probability calculation.

A rectangular hard box separates into three one-dimensional wells. If its side lengths are Lx,Ly,LzL_x,L_y,L_z, then

ψ=Xnx(x)Yny(y)Znz(z),Enxnynz=π2ℏ22m(nx2Lx2+ny2Ly2+nz2Lz2),\psi=X_{n_x}(x)Y_{n_y}(y)Z_{n_z}(z), \qquad E_{n_xn_yn_z}=\frac{\pi^2\hbar^2}{2m} \left(\frac{n_x^2}{L_x^2}+\frac{n_y^2}{L_y^2}+\frac{n_z^2}{L_z^2}\right),

where each quantum number is a positive integer. Multiplying the three normalized factors gives a normalized spatial state. Adding their energies works because the Hamiltonian is a sum of independent coordinate Hamiltonians on a product domain.

Not every state in this box is a single product. Superpositions of product eigenfunctions are also allowed, and some cannot be factored. Nor does every three-dimensional potential separate: a coupling such as xyxy generally defeats separation in the original Cartesian coordinates. A useful coordinate change must simplify both the equation and its boundaries.

For a central potential, spherical coordinates separate angular motion from radial motion. Start with Spherical Coordinates if the volume measure or Laplacian is unfamiliar, then follow Angular and Radial Separation.

Page What you will learn
Schrödinger Equation in Three Dimensions Equation of motion, volume normalization, current, and boundary data
Separation of Variables Product modes, separation constants, coordinate choice, and failure conditions
Three-Dimensional Box Hard-wall products, additive spectrum, labels, and cubic degeneracy
Free Particle in Three Dimensions Momentum vectors, energy shells, delta normalization, and spherical waves
Spherical Coordinates Coordinate convention, Jacobian, unit vectors, gradient, and Laplacian
Angular and Radial Separation Spherical harmonics, radial equation, reduced wavefunction, and centrifugal term
Degeneracy in Separable Systems Eigenspace dimension, sources of repeated energies, and splitting
Density of States: First Encounter Large-box shell counting and the spinless free-particle D(E)D(E)

For a first calculation, study the box before moving to spherical coordinates. Use free particles and the density of states when a question asks how many momentum states fit within an energy interval. The density of states is a smoothed count in a large system; an individual finite box still has discrete levels.

In a cubic box of side LL, find the ground-state energy and the degeneracy of the first excited energy, excluding spin. What happens if only LxL_x is slightly increased?

Solution

Write E0=π2ℏ2/(2mL2)E_0=\pi^2\hbar^2/(2mL^2). The ground state (1,1,1)(1,1,1) has energy 3E03E_0. The states (2,1,1)(2,1,1), (1,2,1)(1,2,1), and (1,1,2)(1,1,2) all have energy 6E06E_0, so the first excited level has degeneracy three. Increasing LxL_x lowers the xx contribution most for (2,1,1)(2,1,1); that state separates from the other two. Equality of the remaining yy and zz lengths keeps their pair degenerate in this rectangular model.

A normalized isotropic state is written ψ(r)=R(r)/4π\psi(\mathbf r)=R(r)/\sqrt{4\pi}. What is the probability in a thin spherical shell?

Solution

Integrating the angular factor over dΩd\Omega gives one. Thus the probability between rr and r+drr+dr is r2∣R(r)∣2 drr^2|R(r)|^2\,dr, to first order in the shell thickness. The factor r2r^2 counts the growing shell volume; ∣R∣2 dr|R|^2\,dr alone is not the radial probability.

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