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Drude theory is the single-relaxation-time model of charge-current response. It assumes that a carrier’s mean drift momentum accelerates under an electric field and relaxes exponentially toward equilibrium:

dpddt=qE−pdτ.\frac{d\mathbf p_d}{dt} = q\mathbf E - \frac{\mathbf p_d}{\tau}.

For an isotropic parabolic band, pd=m∗vd\mathbf p_d=m^*\mathbf v_d. The resulting dc conductivity is

σ0=nq2τm∗.\sigma_0 = \frac{nq^2\tau}{m^*}.

This formula looks classical, but its successful modern use is usually Drude–Sommerfeld: carrier density comes from Fermi statistics and band filling, the response-appropriate m∗m^* from band structure and any necessary interaction corrections, and τ\tau from momentum-relaxing scattering near the Fermi surface. The model does not predict those inputs. It organizes them into a low-frequency response.

The derivation below connects the drift equation to dc, ac and Hall response, then tests what can be inferred from a fitted relaxation time. Transport coefficients explains the broader transport limits, Kubo formula gives the correlation-function formulation, and Effective mass distinguishes the masses measured by different probes.

Required background. Effective Mass supplies the response-specific mass distinctions used here without rederivation.

Helpful background. Fermi Surface supplies low-energy phase space, Metals, Insulators, and Semiconductors supplies carrier and filling classification, and Transport Coefficients Preview supplies the bulk, ballistic, hydrodynamic, and limit-order taxonomy.

Let qq be the signed carrier charge. Thus q=−eq=-e for an electron and q=+eq=+e for a hole. The microscopic carrier velocity can be large even in equilibrium, but opposite directions cancel. vd\mathbf v_d denotes only the small nonequilibrium drift average.

For an isotropic band and zero magnetic field,

m∗dvddt=qE(t)−m∗vdτ.m^* \frac{d\mathbf v_d}{dt} = q\mathbf E(t) - \frac{m^*\mathbf v_d}{\tau}.

The relaxation term asserts:

  • linear response in the drift velocity;
  • local, memoryless damping;
  • one momentum-relaxation time τ\tau;
  • a fixed carrier density and effective mass;
  • spatially uniform response;
  • no distinction among directions, bands, or points on the Fermi surface.

Those are model assumptions, not definitions of a metal.

After transients from the remote past have decayed,

vd(t)=qm∗∫−∞tdt′ e−(t−t′)/τE(t′).\mathbf v_d(t) = \frac{q}{m^*} \int_{-\infty}^{t} dt'\, e^{-(t-t')/\tau} \mathbf E(t').

The response kernel is causal: only earlier fields contribute.

If a constant field E0\mathbf E_0 is switched on at t=0t=0 and the initial drift is zero,

vd(t)=qτm∗E0(1−e−t/τ).\mathbf v_d(t) = \frac{q\tau}{m^*} \mathbf E_0 \left( 1-e^{-t/\tau} \right).

If the field is switched off after steady state is reached, the current decays as e−t/τe^{-t/\tau}. This is the operational meaning of the model’s relaxation time.

τ\tau is a transport momentum-relaxation time. It need not equal:

  • the interval between all microscopic collisions;
  • a single-particle quantum lifetime from spectral broadening;
  • a phase-coherence time;
  • an energy-relaxation time;
  • a recombination time;
  • an escape time from a finite device.

A collision that changes momentum only slightly can strongly broaden a single-particle phase while relaxing current inefficiently. Naming the lifetime is part of reporting it.

In a time-independent field, the steady drift is

vd=qτm∗E.\mathbf v_d = \frac{q\tau}{m^*} \mathbf E.

The current density is

j=nqvd.\mathbf j = nq\mathbf v_d.

Although electron drift is opposite to E\mathbf E, multiplying by the negative electron charge makes the conventional current parallel to E\mathbf E. Therefore

j=σ0E,σ0=nq2τm∗.\mathbf j = \sigma_0\mathbf E, \qquad \sigma_0 = \frac{nq^2\tau}{m^*}.

The resistivity is

ρ0=1σ0=m∗nq2τ.\rho_0 = \frac{1}{\sigma_0} = \frac{m^*}{nq^2\tau}.

Define the positive mobility

μ=∣q∣τm∗.\mu = \frac{|q|\tau}{m^*}.

Then

σ0=n∣q∣μ.\sigma_0 = n|q|\mu.

Conductivity is a bulk coefficient. Conductance also depends on sample geometry and contacts. For a uniform bar of length LL and cross-sectional area AA,

G=σ0AL,G = \sigma_0 \frac{A}{L},

only when current distribution and contact effects permit the elementary geometry reduction.

The original Drude model treated carriers as a classical gas. That picture gives incorrect electronic heat capacity and misses Pauli blocking, band structure, and Fermi-surface geometry. Modern use keeps the momentum-balance equation while replacing its inputs.

nn is obtained from the occupied electronic states, not from a classical Maxwell distribution. In a simple monovalent metal it may be comparable to one carrier per atom; in a doped semiconductor or semimetal it can be many orders of magnitude smaller. In a multiband system there is no single nn unless a reduction is justified.

The mass in a Drude fit is fixed by the current response. For a noninteracting parabolic band it is the band mass; in an interacting crystal it need not equal the quasiparticle mass inferred from a spectral dispersion or heat capacity. Current-vertex corrections matter. Conversely, for a translation-invariant continuum with kinetic energy p2/(2m0)p^2/(2m_0) and interactions depending only on relative coordinates, the uniform current is qP/m0q\mathbf P/m_0. Its clean weight retains m0m_0, even if quasiparticles have a different effective mass. Kohn’s cyclotron-resonance result illustrates this conservation constraint. A real lattice removes that Galilean-invariance argument.

In a degenerate metal, the characteristic velocity for transport is the Fermi velocity rather than a classical thermal velocity. The transport mean free path is

ℓtr=vFτtr.\ell_{\mathrm{tr}} = v_{\mathrm F}\tau_{\mathrm{tr}}.

This connects a time-domain Drude parameter with a spatial semiclassical criterion.

Boltzmann Transport derives the distribution and collision equation. Its simplest weak-field relaxation-time reduction gives

σij=q2∑n∫ddk(2π)d(−∂f∂ε)×vn,i(k)vn,j(k)τn(k).\sigma_{ij} = q^2 \sum_n \int \frac{d^dk}{(2\pi)^d} \left( - \frac{\partial f} {\partial\varepsilon} \right) \times v_{n,i}(\mathbf k) v_{n,j}(\mathbf k) \tau_n(\mathbf k).

Only states in the thermal window around the chemical potential contribute through −∂f/∂ε-\partial f/\partial\varepsilon. For one isotropic parabolic band and constant τ\tau, the integral reduces to nq2τ/m∗nq^2\tau/m^*.

For an isotropic degenerate band, the same physics can be written as an Einstein relation,

σ=q2ρ(EF)D,\sigma = q^2 \rho(E_{\mathrm F}) D,

with

D=vF2τd.D = \frac{v_{\mathrm F}^2\tau}{d}.

Here ρ(EF)\rho(E_{\mathrm F}) is the density of states per dd-dimensional volume, including the degeneracies used in nn; the displayed reduction uses independent quasiparticles with the same transport time. The Drude and diffusion forms agree only when their masses, state counts, and scattering approximations describe the same carriers.

For a parabolic band with mass tensor M\mathsf M and scalar relaxation time,

dvddt+vdτ=qM−1E.\frac{d\mathbf v_d}{dt} + \frac{\mathbf v_d}{\tau} = q\mathsf M^{-1}\mathbf E.

The dc conductivity tensor is

σ0=nq2τM−1.\boldsymbol\sigma_0 = nq^2\tau \mathsf M^{-1}.

In principal axes,

σii=nq2τmi.\sigma_{ii} = \frac{nq^2\tau}{m_i}.

If τ\tau is also anisotropic or momentum dependent, it cannot in general be represented by multiplying M−1\mathsf M^{-1} by one scalar. A measured conductivity anisotropy can come from mass, Fermi-surface geometry, direction-dependent scattering or unequal populations of differently oriented valleys. Changing one scalar density alone does not make an isotropic band anisotropic.

Effective Mass distinguishes the tensor, conductivity, density-of-states, cyclotron, and optical masses used in such reductions.

Use the convention

E(t)=Re⁡[Eωe−iωt].\mathbf E(t) = \operatorname{Re} \left[ \mathbf E_\omega e^{-i\omega t} \right].

The drift equation gives

vω=q/m∗τ−1−iωEω.\mathbf v_\omega = \frac{q/m^*} {\tau^{-1}-i\omega} \mathbf E_\omega.

Therefore

σ(ω)=nq2/m∗τ−1−iω=σ01−iωτ.\sigma(\omega) = \frac{nq^2/m^*} {\tau^{-1}-i\omega} = \frac{\sigma_0} {1-i\omega\tau}.

The pole lies at ω=−i/τ\omega=-i/\tau, in the lower half-plane as required for a retarded response.

The dissipative and reactive parts are

Re⁡σ(ω)=σ01+ω2τ2,\operatorname{Re}\sigma(\omega) = \frac{\sigma_0} {1+\omega^2\tau^2}, Im⁡σ(ω)=σ0ωτ1+ω2τ2.\operatorname{Im}\sigma(\omega) = \frac{\sigma_0\omega\tau} {1+\omega^2\tau^2}.

The cycle-averaged absorbed power density is

P‾=12Re⁡σ(ω)∣Eω∣2.\overline P = \frac{1}{2} \operatorname{Re}\sigma(\omega) |\mathbf E_\omega|^2.

Re⁡σ\operatorname{Re}\sigma is a Lorentzian centered at zero frequency with half width

γ=1τ.\gamma = \frac{1}{\tau}.

For ωτ≪1\omega\tau\ll1, the current nearly follows the field. For ωτ≫1\omega\tau\gg1, collisions are too slow to establish the dc drift during one cycle and the response is mainly reactive:

σ(ω)≈inq2m∗ω.\sigma(\omega) \approx i \frac{nq^2} {m^*\omega}.

Real and imaginary Drude conductivity versus frequency times relaxation time, above the semicircle traced by the complex conductivity.

For σ/σ0=(1−iωτ)−1\sigma/\sigma_0=(1-i\omega\tau)^{-1}, the dissipative peak has half width 1/τ1/\tau, while the reactive part peaks at ωτ=1\omega\tau=1. At positive frequency the complex conductivity traces the upper semicircle from σ/σ0=1\sigma/\sigma_0=1 toward the origin: (Re⁡σ/σ0−1/2)2+(Im⁡σ/σ0)2=1/4(\operatorname{Re}\sigma/\sigma_0-1/2)^2+(\operatorname{Im}\sigma/\sigma_0)^2=1/4.

Write

D0=nq2m∗.\mathcal D_0 = \frac{nq^2}{m^*}.

Then

Re⁡σ(ω)=D0γγ2+ω2.\operatorname{Re}\sigma(\omega) = \mathcal D_0 \frac{\gamma} {\gamma^2+\omega^2}.

The positive-frequency intraband area is

∫0∞dω Re⁡σ(ω)=π2nq2m∗.\int_0^\infty d\omega\, \operatorname{Re}\sigma(\omega) = \frac{\pi}{2} \frac{nq^2}{m^*}.

Changing τ\tau changes the width and height but not this Drude area. In the clean limit,

lim⁡γ→0+γγ2+ω2=πδ(ω)\lim_{\gamma\to0^+} \frac{\gamma} {\gamma^2+\omega^2} = \pi\delta(\omega)

on the full frequency axis. Thus

Re⁡σ(ω)⟶πD0δ(ω).\operatorname{Re}\sigma(\omega) \longrightarrow \pi\mathcal D_0 \delta(\omega).

Different communities absorb factors of π\pi into the definition of “Drude weight.” A quoted Drude weight must include its conductivity convention.

The optical sum of a continuum Hamiltonian uses the mass appearing in that Hamiltonian. For the full nonrelativistic electron problem this is the bare mass m0m_0; for a projected parabolic band it can be m∗m^*. A projected model has omitted interband transitions and cannot supply the full-electron sum by extending its Drude curve to arbitrarily high energies. In a lattice, intraband weight can depend on band curvature and interactions.

Sum Rules derives exact integrated spectral constraints. The delta-function distinction between an ideal conductor and an insulator is broader than a finite-τ\tau fit and connects to Metals, Insulators, and Semiconductors.

For the e−iωte^{-i\omega t} convention,

ϵ(ω)=ϵ∞+iσ(ω)ϵ0ω.\epsilon(\omega) = \epsilon_\infty + \frac{i\sigma(\omega)} {\epsilon_0\omega}.

Define the Drude plasma frequency

ωp2=nq2ϵ0m∗.\omega_p^2 = \frac{nq^2} {\epsilon_0m^*}.

Then

ϵ(ω)=ϵ∞−ωp2ω(ω+i/τ).\epsilon(\omega) = \epsilon_\infty - \frac{\omega_p^2} {\omega \left( \omega+i/\tau \right)}.

The zero of the longitudinal dielectric function controls a bulk plasma mode after background screening and damping are included. Reflectivity edges, loss-function peaks, and zeros of Re⁡ϵ\operatorname{Re}\epsilon need not coincide when absorption or interband structure is appreciable.

Plasmons Preview derives the self-consistent modes; Plasmons in Materials explains their dielectric environment and geometry.

Include a static magnetic field:

m∗dvddt=q(E+vd×B)−m∗vdτ.m^* \frac{d\mathbf v_d}{dt} = q \left( \mathbf E + \mathbf v_d\times\mathbf B \right) - \frac{m^*\mathbf v_d}{\tau}.

Take B=Bz^\mathbf B=B\hat{\mathbf z} and define the signed cyclotron frequency and field parameter

ωc=qBm∗,βc=ωcτ.\omega_c = \frac{qB}{m^*}, \qquad \beta_c = \omega_c\tau.

In steady state,

σ=σ01+βc2(1βc−βc1).\boldsymbol\sigma = \frac{\sigma_0} {1+\beta_c^2} \begin{pmatrix} 1 & \beta_c \\ -\beta_c & 1 \end{pmatrix}.

The resistivity tensor is

ρ=1σ0(1−βcβc1).\boldsymbol\rho = \frac{1}{\sigma_0} \begin{pmatrix} 1 & -\beta_c \\ \beta_c & 1 \end{pmatrix}.

With the convention

RH=EyjxB=ρyxB,R_H = \frac{E_y} {j_xB} = \frac{\rho_{yx}}{B},

the single-carrier Hall coefficient is

RH=1nq.R_H = \frac{1}{nq}.

It is negative for electrons and positive for holes. The Hall angle has magnitude

∣tan⁡θH∣=∣ωcτ∣.|\tan\theta_H| = |\omega_c\tau|.

The same one-band isotropic model predicts

ρxx(B)=ρ0.\rho_{xx}(B) = \rho_0.

That is, it has zero transverse magnetoresistance despite a field-dependent σxx\sigma_{xx}. Inverting the conductivity tensor matters. Observed magnetoresistance requires additional structure such as multiple carriers, anisotropy, momentum-dependent scattering, open orbits, inhomogeneity, or quantum effects.

For carrier species aa with positive mobility μa\mu_a and sign sa=sgn⁡(qa)s_a=\operatorname{sgn}(q_a),

σxx(B)=∑ana∣qa∣μa1+μa2B2,\sigma_{xx}(B) = \sum_a \frac{ n_a|q_a|\mu_a }{ 1+\mu_a^2B^2 }, σxy(B)=∑asana∣qa∣μa2B1+μa2B2.\sigma_{xy}(B) = \sum_a \frac{ s_a n_a|q_a| \mu_a^2B }{ 1+\mu_a^2B^2 }.

For electrons of density nn and holes of density pp, the weak-field Hall coefficient is

RH=pμh2−nμe2e(pμh+nμe)2.R_H = \frac{ p\mu_h^2 - n\mu_e^2 }{ e \left( p\mu_h+n\mu_e \right)^2 }.

The Hall sign is mobility weighted. A positive RHR_H does not prove that every Fermi-surface sheet is hole-like, and 1/(eRH)1/(eR_H) is not generally the total carrier density. Fermi Surface develops this warning in the context of electron and hole pockets.

The Drude equation does not calculate τ\tau. Candidate momentum-relaxing mechanisms include:

  • impurities and defects;
  • phonons;
  • electron–electron Umklapp;
  • boundaries and interfaces;
  • magnetic fluctuations;
  • coupling to other collective modes;
  • spatial inhomogeneity.

For elastic scattering on an isotropic Fermi surface, a representative transport rate is

1τtr=∑k′Wkk′(1−cos⁡θ).\frac{1}{\tau_{\mathrm{tr}}} = \sum_{\mathbf k'} W_{\mathbf k\mathbf k'} \left( 1-\cos\theta \right).

θ\theta is the angle through which the velocity is scattered. The corresponding single-particle or quantum rate lacks the current-relaxation factor:

1τq=∑k′Wkk′.\frac{1}{\tau_q} = \sum_{\mathbf k'} W_{\mathbf k\mathbf k'}.

Forward scattering can make τtr≫τq\tau_{\mathrm{tr}}\gg\tau_q. Comparing mobility and quantum-oscillation damping as though they measured one lifetime can therefore be misleading.

Independent weak scattering channels are often approximated by

1τtr≈∑a1τa.\frac{1}{\tau_{\mathrm{tr}}} \approx \sum_a \frac{1}{\tau_a}.

This is Matthiessen’s rule. It can fail when channels interfere, scattering is strongly energy dependent or anisotropic, the band structure changes with temperature, or one process modifies the distribution sampled by another.

A measured temperature dependence of ρ\rho is not predicted by Drude theory until a microscopic or empirical τ(T)\tau(T) is supplied.

One slowly relaxing quantity that overlaps strongly with the uniform current can give a dominant low-frequency pole,

σ(ω)≃D0Γ−iω+σreg(ω).\sigma(\omega)\simeq\frac{\mathcal D_0}{\Gamma-i\omega} +\sigma_{\mathrm{reg}}(\omega).

The regular background may be negligible in a restricted frequency range. Microscopic physics then sets the weight and rate; a Drude-like peak does not require the literal classical picture of independent particles between collisions. Rapid momentum-conserving collisions can coexist with slow current decay when current overlaps with an almost conserved momentum. When that overlap vanishes, as it can in a compensated electron–hole system, momentum conservation alone does not protect charge current.

Fermi statistics also changes the interpretation: in a degenerate metal the weak-field occupation change is concentrated near the Fermi surface, even when integration by parts expresses the result through the full density nn. This is consistent with a small electronic heat capacity. A successful low-frequency fit still constrains response parameters, not an independently established microscopic collision mechanism.

For a degenerate Fermi gas with sufficiently elastic, weakly energy-dependent scattering,

κeσT⟶L0,L0=π23(kBe)2.\frac{\kappa_e} {\sigma T} \longrightarrow L_0, \qquad L_0 = \frac{\pi^2}{3} \left( \frac{k_{\mathrm B}}{e} \right)^2.

The quantum Sommerfeld calculation supplies the correct Lorenz number. Deviations can arise from inelastic scattering, additional heat carriers, multiband structure, hydrodynamics, or non-Fermi-liquid behavior.

A general causal intraband response can be parameterized as

σ(ω)=ϵ0ωp2M(ω)−iω,\sigma(\omega) = \frac{\epsilon_0\omega_p^2} {M(\omega)-i\omega},

where M(ω)M(\omega) is a memory function. Ordinary Drude theory takes

M(ω)=1τ.M(\omega) = \frac{1}{\tau}.

Given a chosen intraband plasma frequency, optical analyses sometimes define

1τop(ω)=ϵ0ωp2Re⁡[1σ(ω)],\frac{1} {\tau_{\mathrm{op}}(\omega)} = \epsilon_0\omega_p^2 \operatorname{Re} \left[ \frac{1}{\sigma(\omega)} \right], mop(ω)mb=−ϵ0ωp2ωIm⁡[1σ(ω)].\frac{m_{\mathrm{op}}(\omega)} {m_b} = - \frac{\epsilon_0\omega_p^2} {\omega} \operatorname{Im} \left[ \frac{1}{\sigma(\omega)} \right].

For a perfect Drude response these give 1/τ1/\tau and 11. For real data they are derived optical functions, not direct measurements of a microscopic collision clock and mass. Their values depend on the chosen plasma frequency and on how interband, phonon, and collective contributions are subtracted.

Dc resistivity fixes nτ/m∗=1/(q2ρ0)n\tau/m^*=1/(q^2\rho_0), while a resolved complex optical spectrum can constrain a Drude area and width separately. Even optics does not independently determine nn and m∗m^*. The review by Basov and collaborators discusses why low-energy optical weight and current relaxation have to be interpreted together in correlated materials.

Several bands can contribute different widths, and interband or phonon absorption can overlap them. Their sum can produce a frequency-dependent extended-Drude rate even when each individual band has a constant time; Exercise 4 gives an exact example. A causal fit to both real and imaginary response, checked against dc transport and the partial optical sum, is more informative than fitting one peak. Terahertz and infrared probes explains the sample-stack inversion needed first.

In Hall measurements, field reversal helps separate transverse and longitudinal signals when the material state is unchanged apart from the specified reversal. Magnetic hysteresis or an independently ordered magnetization requires additional care. A nonlinear Hall curve rules out the simplest constant-parameter one-carrier model, but a linear curve alone does not establish it. Hall effect treats multiple carriers and anomalous contributions.

The extended-state drift picture itself fails for localized or hopping carriers. The heuristic condition kFℓtr≲1k_F\ell_{\mathrm{tr}}\lesssim1 warns against interpreting a fitted time as well-separated quasiparticle collisions; it is not a universal sharp resistivity bound. Viscous flow, ballistic contacts and nonlocal electrodynamics depend on geometry in ways one local time cannot capture. Large fields can heat carriers or change their state, and Landau quantization can invalidate the smooth classical magnetic response. These limits are developed in Boltzmann transport, weak localization and mesoscopic physics.

A zero-frequency delta weight is broader than superconductivity: a clean normal conductor can also have one. Identifying a superconducting state requires the additional phase and magnetic response discussed in Superfluidity and Superconductivity.

Take

n=5.0×1028 m−3,ρ0=2.0×10−8 Ω m,n = 5.0\times10^{28}\,\mathrm{m^{-3}}, \qquad \rho_0 = 2.0\times10^{-8}\,\Omega\,\mathrm m,

with m∗=m0m^*=m_0 in a three-dimensional spin-degenerate parabolic band at low temperature. Derive kFk_F and vFv_F from the density, then estimate τ\tau, mobility and mean free path.

Solution

For this band, state counting gives kF=(3π2n)1/3≃1.140×1010 m−1k_F=(3\pi^2n)^{1/3}\simeq1.140\times10^{10}\,\mathrm{m^{-1}}. Consequently vF=ℏkF/m0≃1.32×106 m/sv_F=\hbar k_F/m_0\simeq1.32\times10^6\,\mathrm{m/s}; the Fermi velocity is not a further independent input. From ρ0=m0/(ne2τ)\rho_0=m_0/(ne^2\tau),

τ=m0ne2ρ0≈3.6×10−14 s.\tau = \frac{m_0} {ne^2\rho_0} \approx 3.6\times10^{-14}\,\mathrm s.

The mobility is

μ=eτm0≈6.3×10−3 m2 V−1 s−1,\mu = \frac{e\tau}{m_0} \approx 6.3\times10^{-3}\, \mathrm{m^2\,V^{-1}\,s^{-1}},

or about 63 cm2 V−1 s−163\,\mathrm{cm^2\,V^{-1}\,s^{-1}}. The mean free path is

ℓ=vFτ≈4.7×10−8 m,\ell = v_{\mathrm F}\tau \approx 4.7\times10^{-8}\,\mathrm m,

about 47 nm47\,\mathrm{nm}. These values inherit the assumed one-band mass and density.

A compensated semimetal has n=pn=p, but μh=2μe\mu_h=2\mu_e. What is the sign of its weak-field Hall coefficient?

Solution

For n=pn=p,

RH=nμh2−nμe2en2(μh+μe)2.R_H = \frac{ n\mu_h^2-n\mu_e^2 }{ en^2 \left( \mu_h+\mu_e \right)^2 }.

Since

μh2−μe2=4μe2−μe2>0,\mu_h^2-\mu_e^2 = 4\mu_e^2-\mu_e^2 > 0,

RHR_H is positive. The material is exactly carrier compensated, yet the more mobile holes control the weak-field Hall sign.

Suppose scattering is concentrated at a small angle θ0≪1\theta_0\ll1. Compare its contributions to 1/τq1/\tau_q and 1/τtr1/\tau_{\mathrm{tr}}.

Solution

The quantum rate counts the event with weight approximately one. The transport rate includes

1−cos⁡θ0≈θ022.1-\cos\theta_0 \approx \frac{\theta_0^2}{2}.

Thus the same forward-scattering channel contributes much less to current relaxation:

τtr−1τq−1∼θ022.\frac{ \tau_{\mathrm{tr}}^{-1} }{ \tau_q^{-1} } \sim \frac{\theta_0^2}{2}.

Consequently τtr\tau_{\mathrm{tr}} can be much longer than τq\tau_q.

4. Frequency-dependent optical rates from constant-time bands

Section titled “4. Frequency-dependent optical rates from constant-time bands”

Two independent carrier bands each have the same weight DD, with relaxation rates Γ\Gamma and 4Γ4\Gamma. Their conductivities add:

σ(ω)=DΓ−iω+D4Γ−iω.\sigma(\omega)=\frac{D}{\Gamma-i\omega} +\frac{D}{4\Gamma-i\omega}.

Use the total weight 2D2D to define the optical rate and mass ratio above. Find their dependence on x=ω/Γx=\omega/\Gamma. Does a frequency-dependent optical rate prove that a band’s microscopic scattering rate depends on frequency?

Solution

First combine the two response functions before inverting:

2Dσ(ω)=2Γ(1−ix)(4−ix)5−2ix.\frac{2D}{\sigma(\omega)} =2\Gamma\frac{(1-ix)(4-ix)}{5-2ix}.

The real and imaginary parts give

τop−1(ω)Γ=40+10x225+4x2,mop(ω)mb=34+4x225+4x2.\begin{aligned} \frac{\tau_{\mathrm{op}}^{-1}(\omega)}{\Gamma} &=\frac{40+10x^2}{25+4x^2},\\ \frac{m_{\mathrm{op}}(\omega)}{m_b} &=\frac{34+4x^2}{25+4x^2}. \end{aligned}

The rate rises from 1.6Γ1.6\Gamma to 2.5Γ2.5\Gamma, and the mass ratio decreases from 1.361.36 to 1, although each band’s microscopic rate is constant. The x=0x=0 mass value is its continuous limit. Both original responses are causal and have positive absorption. The derived functions reflect their mixture; they do not identify a unique single-band self-energy or an interaction-induced mass enhancement.

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