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Mutual Information in Many-Body Systems

Quantum mutual information measures the total correlation between two declared parts of a many-body state. Let the full system be divided into disjoint regions

Ω=A⊔B⊔C,\Omega = A\sqcup B\sqcup C,

where CC may be empty. Starting from a state ρΩ\rho_\Omega, form

ρAB=Tr⁡CρΩ.\rho_{AB} = \operatorname{Tr}_C\rho_\Omega.

The mutual information is

I(A:B)ρ:=S(ρA)+S(ρB)−S(ρAB).I(A:B)_\rho := S(\rho_A) + S(\rho_B) - S(\rho_{AB}).

This combination answers a sharper question than either regional entropy alone:

How much of the uncertainty in AA and BB is shared rather than independent?

In a mixed thermal state, S(ρA)S(\rho_A) and S(ρB)S(\rho_B) can both be extensive even when the state has no correlations at all. Their independent bulk contributions cancel in I(A:B)I(A:B). In a pure state split into complementary regions, by contrast, the mutual information is twice the entanglement entropy. Between separated regions it probes all correlation channels at once, including classical, quantum, symmetry-sector, constraint-induced, and long-range contributions.

That breadth is both the strength and the main caution. Nonzero mutual information does not by itself prove entanglement, identify a phase, locate a critical point, or reveal which observables carry the correlation.

Helpful background. Mutual information supplies the finite-system definition and relative-entropy identity; connected correlation functions explains the operator correlations bounded below.

Unless stated otherwise:

  • ρΩ\rho_\Omega is a normalized state on a finite lattice Hilbert space;
  • AA and BB are disjoint sets of sites, orbitals, modes, or local degrees of freedom;
  • C=Ω∖(A∪B)C=\Omega\setminus(A\cup B) is the environment traced out before evaluating I(A:B)I(A:B);
  • S(ρ)=−Tr⁡(ρln⁡ρ)S(\rho)=-\operatorname{Tr}(\rho\ln\rho) uses natural logarithms, so information is measured in nats;
  • continuum and gauge-theory statements require additional regulator and algebra choices.

The subsystem choice is physical data. A spatial region, a momentum-space block, an orbital set, and a particle partition generally produce different reduced states and different mutual informations.

The same formula appears in three geometrically distinct settings.

Geometry Environment CC Typical question
complementary cut B=AˉB=\bar A empty how much total correlation crosses one cut?
adjacent AA and BB inside Ω\Omega nonempty or empty how much correlation is localized near their shared interface?
separated AA and BB nonempty buffer how does total correlation decay with separation?

These geometries should not be compared without matching sizes, boundaries, separation, total volume, and state preparation.

Changing the logarithm base rescales every entropy and mutual information by the same constant. With base 22,

Ibits(A:B)=I(A:B)ln⁡2I_{\mathrm{bits}}(A:B) = \frac{I(A:B)}{\ln2}

is measured in bits. The descriptive subscript distinguishes this base change from a second Rényi mutual information; a superscript such as I(2)I^{(2)} is reserved for Rényi constructions.

The central identity is

I(A:B)ρ=D ⁣(ρAB∥ρA⊗ρB),I(A:B)_\rho = D\!\left( \rho_{AB} \middle\| \rho_A\otimes\rho_B \right),

where D(ρ∥σ)D(\rho\|\sigma) is quantum relative entropy. Therefore

I(A:B)ρ≥0,I(A:B)_\rho \ge 0,

with equality exactly when

ρAB=ρA⊗ρB.\rho_{AB} = \rho_A\otimes\rho_B.

The comparison product uses the actual marginals of the state. Mutual information removes local mixedness while retaining every deviation of the joint state from independence.

The Araki–Lieb inequality gives

I(A:B)≤2min⁡{SA,SB}.I(A:B) \le 2\min\{S_A,S_B\}.

For finite local Hilbert spaces,

I(A:B)≤2ln⁡min⁡{dA,dB}.I(A:B) \le 2\ln\min\{d_A,d_B\}.

These are dimension bounds, not expected scaling laws. A much smaller value can follow from locality, temperature, separation, symmetry, or the state class.

Local quantum channels cannot increase mutual information. If ΦA\Phi_A and ΦB\Phi_B act independently,

I(A′:B′)(ΦA⊗ΦB)(ρ)≤I(A:B)ρ.I(A':B')_{(\Phi_A\otimes\Phi_B)(\rho)} \le I(A:B)_\rho.

In particular, discarding degrees of freedom cannot reveal more total correlation:

A⊆A′,B⊆B′,I(A:B)≤I(A′:B′).\begin{aligned} A&\subseteq A', &B&\subseteq B', \\ I(A:B)&\le I(A':B'). \end{aligned}

This monotonicity is useful when comparing single sites, small blocks, and enlarged blocks. It also explains why coarse local measurements provide lower bounds rather than exact reconstructions of the quantum mutual information.

Independent unitary changes of basis inside the regions preserve the value:

I(A:B)(UA⊗UB)ρ(UA†⊗UB†)=I(A:B)ρ.I(A:B)_{(U_A\otimes U_B)\rho(U_A^\dagger\otimes U_B^\dagger)} = I(A:B)_\rho.

An orbital or mode transformation that mixes AA with BB changes the partition and need not preserve it.

If the global state on ABAB is pure,

SAB=0,SA=SB,S_{AB}=0, \qquad S_A=S_B,

and hence

I(A:B)=2SA.I(A:B) = 2S_A.

For a complementary pure-state cut, mutual information contains no independent information beyond the entanglement entropy. The factor of two matters: a single Bell pair crossing the cut contributes ln⁡2\ln2 to SAS_A and 2ln⁡22\ln2 to I(A:B)I(A:B).

Now let ABCABC be pure and trace out a nonempty CC. Then

SAB=SC,S_{AB}=S_C,

so

I(A:B)=SA+SB−SC.I(A:B) = S_A+S_B-S_C.

This is generally smaller than 2min⁡{SA,SB}2\min\{S_A,S_B\}. Correlations that either region shares with CC do not automatically become correlations between AA and BB.

The distinction is crucial for spatial studies. Two disjoint intervals in a pure chain have a mixed joint state because the sites between and outside them were traced out.

Suppose the global state is a product of local states and n∂n_\partial Bell pairs, each crossing a complementary spatial cut. Then

SA=n∂ln⁡2,S_A = n_\partial\ln2,

and

I(A:Aˉ)=2n∂ln⁡2.I(A:\bar A) = 2n_\partial\ln2.

The mutual information therefore obeys the same boundary count, with twice the pure-state entropy coefficient. This fixed-point example motivates an area law but does not prove one for generic interacting states.

Tracing one GHZ spin reduces mutual information; an Ising dimer has purely classical mutual information

Two exact examples distinguish total correlation from entanglement. In the three-spin GHZ state, I(A:BC)=2ln⁡2I(A:BC)=2\ln2; after tracing out CC, the remaining two-spin state is a separable classical mixture with I(A:B)=ln⁡2I(A:B)=\ln2. The lower plot shows the separable Ising-dimer Gibbs state: its mutual information approaches one classical bit, while the connected ZZ correlator gives the lower bound I≥12tanh⁡2xI\ge\tfrac12\tanh^2x, with x=βJx=\beta J.

When AA and BB share a boundary, short-distance degrees of freedom can correlate strongly across that interface. In a short-range thermal state, the leading volume entropy cancels, leaving an interface-controlled contribution under suitable assumptions.

On a lattice the result is finite. In a continuum theory with a sharp shared boundary, the individual entropies and their combination can retain ultraviolet sensitivity. Adjacency should not be confused with the regulator-independent separated-region construction.

Let rr denote the minimum distance between AA and BB. For separated regions, the buffer CC removes a shared ultraviolet boundary. In many gapped ground states and noncritical thermal states, I(A:B)I(A:B) decreases rapidly when

r≫ξ,r \gg \xi,

where ξ\xi is an appropriate correlation length. The precise upper bound and decay law require assumptions about locality, the state family, region sizes, and sometimes the phase.

At criticality, scale invariance can replace exponential decay by a power-law or cross-ratio dependence. The functional form is theory and geometry dependent; a generic power law should not be assigned a universal exponent without specifying the operator content and limiting regime.

Two single-site regions may have weak mutual information while two larger blocks at the same separation have a substantial value because many weak channels accumulate. Report at least

∣A∣,∣B∣,r,L,|A|, \qquad |B|, \qquad r, \qquad L,

along with boundary conditions and shape.

Mutual Information and Connected Correlators

Section titled “Mutual Information and Connected Correlators”

Let OAO_A and OBO_B be bounded operators supported in AA and BB. Define the connected correlator

CAB(OA,OB):=⟨OAOB⟩−⟨OA⟩⟨OB⟩.C_{AB}(O_A,O_B) := \langle O_AO_B\rangle - \langle O_A\rangle \langle O_B\rangle.

Because

CAB=Tr⁡[(ρAB−ρA⊗ρB)OA⊗OB],C_{AB} = \operatorname{Tr} \left[ \left( \rho_{AB}-\rho_A\otimes\rho_B \right) O_A\otimes O_B \right],

trace-norm duality gives

∣CAB∣≤∥ρAB−ρA⊗ρB∥1∥OA∥ ∥OB∥.|C_{AB}| \le \left\| \rho_{AB}-\rho_A\otimes\rho_B \right\|_1 \|O_A\|\,\|O_B\|.

Quantum Pinsker inequality in nats states

I(A:B)≥12∥ρAB−ρA⊗ρB∥12.I(A:B) \ge \frac12 \left\| \rho_{AB}-\rho_A\otimes\rho_B \right\|_1^2.

Combining the two yields

I(A:B)≥∣CAB(OA,OB)∣22∥OA∥2∥OB∥2.I(A:B) \ge \frac{ |C_{AB}(O_A,O_B)|^2 }{ 2\|O_A\|^2\|O_B\|^2 }.

Thus any nonzero bounded connected correlator proves nonzero mutual information. Conversely, sufficiently small mutual information forces every bounded connected correlator between the two regions to be small.

The converse does not follow from a short operator list

Section titled “The converse does not follow from a short operator list”

Suppose numerical data show

CAB(OA(k),OB(k))≈0C_{AB}(O_A^{(k)},O_B^{(k)}) \approx 0

for several selected pairs. This does not prove I(A:B)≈0I(A:B)\approx0. The reduced state may contain:

  • higher-order correlations;
  • correlations in an unmeasured symmetry channel;
  • string or loop correlations;
  • a shared conserved-sector label;
  • correlations distributed over many individually weak operators.

Full mutual information summarizes the entire ρAB\rho_{AB}, whereas a correlator probes one direction in operator space.

If normalized bounded order-parameter operators retain

lim⁡r→∞∣CAB(r)∣>0,\lim_{r\to\infty} |C_{AB}(r)| > 0,

the lower bound prevents I(A:B)I(A:B) from vanishing at large separation. The reverse statement needs care: nonvanishing mutual information may come from a global constraint, a finite-volume cat state, or another channel rather than the proposed order parameter.

For an unconstrained lattice with local Hilbert-space dimensions dAd_A and dBd_B, the infinite-temperature state factorizes:

ρ0=IAdA⊗IBdB.\rho_0 = \frac{I_A}{d_A} \otimes \frac{I_B}{d_B}.

Although

SA=ln⁡dA,SB=ln⁡dB,S_A=\ln d_A, \qquad S_B=\ln d_B,

the joint entropy is their sum, and

I(A:B)=0.I(A:B)=0.

This is the cleanest demonstration that extensive local entropy is not correlation and not entanglement.

In a regular homogeneous thermal phase, suppose

SA=sthVA+δA,SB=sthVB+δB,SAB=sth(VA+VB)+δAB.\begin{aligned} S_A &= s_{\mathrm{th}}V_A+\delta_A, \\ S_B &= s_{\mathrm{th}}V_B+\delta_B, \\ S_{AB} &= s_{\mathrm{th}}(V_A+V_B)+\delta_{AB}. \end{aligned}

Then

I(A:B)=δA+δB−δAB.I(A:B) = \delta_A+\delta_B-\delta_{AB}.

The volume term cancels exactly. The remainder may contain interface, corner, finite-size, conservation-law, critical, or long-range-interaction contributions.

The cancellation is algebraic, but extracting the small remainder numerically can be difficult because it subtracts three much larger quantities.

Take AA and BB to be complementary parts of a finite tensor-product Hilbert space, and let

ρAB=e−βHZ,β>0,\rho_{AB} = \frac{e^{-\beta H}}{Z},\qquad \beta>0,

where the trace defining ZZ runs over that full space. Use a local decomposition

H=HA+HB+H∂,H = H_A+H_B+H_\partial,

where H∂H_\partial contains interactions crossing the cut. The product ρA⊗ρB\rho_A\otimes\rho_B has the same expectations of HAH_A and HBH_B as ρAB\rho_{AB}.

The product trial state is admissible in this unconstrained Gibbs problem. Positivity of D(ρA⊗ρB∥ρAB)D(\rho_A\otimes\rho_B\|\rho_{AB}) gives the bound directly:

D(ρA⊗ρB∥ρAB)=βTr⁡[H∂(ρA⊗ρB−ρAB)]−I(A:B)≥0.D(\rho_A\otimes\rho_B\|\rho_{AB}) ={}\beta\operatorname{Tr}[H_\partial(\rho_A\otimes\rho_B-\rho_{AB})] -I(A:B)\ge0.

Consequently,

I(A:B)≤βTr⁡[H∂(ρA⊗ρB−ρAB)].I(A:B) \le \beta \operatorname{Tr} \left[ H_\partial \left( \rho_A\otimes\rho_B-\rho_{AB} \right) \right].

Using the operator norm,

I(A:B)≤2β∥H∂∥.I(A:B) \le 2\beta\|H_\partial\|.

For bounded finite-range interactions with

∥H∂∥≤J∣∂EA∣,\|H_\partial\| \le J|\partial_E A|,

one obtains

I(A:B)≤2βJ∣∂EA∣.I(A:B) \le 2\beta J|\partial_E A|.

This is a thermal area-law upper bound. It can be loose, especially as β\beta grows. Projection onto a fixed total charge changes the hypothesis: the product of the marginals may leave that sector, so this trial-state argument no longer applies. The one-particle example below has positive mutual information even for H=0H=0 restricted to its fixed-number sector.

For embedded or separated A,BA,B in a larger Gibbs system Ω\Omega, ρAB\rho_{AB} is generally not a Gibbs state of HA+HBH_A+H_B plus their direct interface. Instead data processing gives I(A:B)≤I(A:Ω∖A)I(A:B)\le I(A:\Omega\setminus A), to which the full Gibbs boundary bound applies. Area laws explains the boundary conventions.

Consider two spins with

H=−Jσ1zσ2z,x:=βJ,J>0,β>0.H = -J\sigma_1^z\sigma_2^z, \qquad x:=\beta J,\qquad J>0,\quad\beta>0.

The Gibbs state is diagonal and separable. Both one-spin marginals are maximally mixed, while the joint probabilities favor aligned outcomes. Its mutual information is

I(1:2)=xtanh⁡x−ln⁡cosh⁡x.I(1:2) = x\tanh x - \ln\cosh x.

At high temperature,

I(1:2)=x22−x44+O(x6).I(1:2) = \frac{x^2}{2} - \frac{x^4}{4} + O(x^6).

At zero temperature approached through the Gibbs state,

I(1:2)⟶ln⁡2.I(1:2) \longrightarrow \ln2.

The limiting state is the classical mixture of the two aligned configurations. The nonzero result is one shared classical bit, not entanglement.

Thermal entanglement is a separate question

Section titled “Thermal entanglement is a separate question”

An interacting Gibbs state can be entangled at nonzero temperature. Mutual information then combines the quantum contribution with all classical and thermal correlations. To isolate entanglement, use a measure or witness appropriate to the bipartition, such as negativity and the PPT criterion where applicable.

The implication is one-way:

I(A:B)=0⟹no entanglement,I(A:B)=0 \quad\Longrightarrow\quad \text{no entanglement},

but

I(A:B)>0I(A:B)>0

does not distinguish separable from entangled states.

The phrase “infinite temperature” is incomplete without the ensemble. The maximally mixed state on the full tensor-product Hilbert space factorizes. The maximally mixed state inside a fixed total-charge sector generally does not.

Consider one particle uniformly mixed over LL sites:

ρ(1)=1L∑j=1L∣j⟩⟨j∣.\rho^{(1)} = \frac1L \sum_{j=1}^{L} \lvert j\rangle\langle j\rvert.

Partition the lattice into LA=fLL_A=fL and LB=(1−f)LL_B=(1-f)L sites. Region AA is either empty or contains the particle. Its entropy is

SA=H2(f)+fln⁡LA,S_A = H_2(f) + f\ln L_A,

where

H2(f):=−fln⁡f−(1−f)ln⁡(1−f).H_2(f) := -f\ln f -(1-f)\ln(1-f).

Similarly,

SB=H2(f)+(1−f)ln⁡LB,S_B = H_2(f) + (1-f)\ln L_B,

while

SAB=ln⁡L.S_{AB}=\ln L.

The mutual information is therefore

I(A:B)=H2(f).I(A:B) = H_2(f).

At f=1/2f=1/2, the fixed-number constraint contributes ln⁡2\ln2. This is not an interaction-generated correlation; it is the shared information that if the particle is in one region it is absent from the other.

Canonical versus grand-canonical comparisons

Section titled “Canonical versus grand-canonical comparisons”

At finite size, global conservation can produce constant, logarithmic, or other subextensive contributions absent from an unconstrained ensemble. A reliable comparison records:

  • whether total charge, magnetization, momentum, or parity is fixed;
  • whether the reduced state retains block labels;
  • whether the same ensemble is used at every size;
  • which limit is taken before the subsystem fraction is fixed.

Ensemble Equivalence explains when local thermodynamic predictions converge and why information measures can remain sensitive to global constraints at finite size.

Ordered, Critical, and Topological Regimes

Section titled “Ordered, Critical, and Topological Regimes”

For the NN-spin GHZ state

∣GHZN⟩=∣0⟩⊗N+∣1⟩⊗N2,\lvert\mathrm{GHZ}_N\rangle = \frac{ \lvert0\rangle^{\otimes N} + \lvert1\rangle^{\otimes N} }{\sqrt2},

every nonempty proper region has entropy ln⁡2\ln2. If nonempty disjoint AA and BB do not cover the whole system,

SA=SB=SAB=ln⁡2,S_A=S_B=S_{AB}=\ln2,

and

I(A:B)=ln⁡2.I(A:B)=\ln2.

After tracing CC, the coherence between the two global branches is lost, but the shared branch label remains. For a complementary cut,

I(A:Aˉ)=2ln⁡2.I(A:\bar A)=2\ln2.

This difference is a geometry effect, not a contradiction.

In a symmetry-broken phase, a finite-volume symmetric cat state and a phase-selected thermodynamic state can therefore have different long-distance mutual information. State preparation and order of limits must be declared.

At a continuous transition, long-distance correlations can make block mutual information scale nonanalytically with region size, separation, temperature, or a conformal cross-ratio. This makes mutual information useful for finite-size scaling.

It does not make the location of a maximum universal. Classical and quantum studies show that peaks, crossings, cusps, and subleading singularities depend on:

  • the chosen regions;
  • whether von Neumann or Rényi quantities are used;
  • boundary and corner geometry;
  • subsystem fraction;
  • analytic background terms;
  • finite-size corrections.

A trustworthy critical analysis uses a scaling ansatz and several sizes. It does not identify a transition from one peak alone. Entanglement and criticality and quantum phase transitions develop the scaling analysis.

Mutual information can enter subtraction schemes that cancel local boundary terms, and separated-region patterns can help reveal nonlocal organization. A single value of I(A:B)I(A:B) is nevertheless not a topological invariant. Classical constraints, symmetry breaking, gauge constraints, and ordinary long-range correlations can all produce nonlocal mutual information.

Topological order explains local indistinguishability, global sectors, loop algebra, anyons, and topological entropy.

For sharply separated continuum regions,

dist⁡(A,B)>0,\operatorname{dist}(A,B)>0,

the local ultraviolet divergences in SAS_A, SBS_B, and SA∪BS_{A\cup B} cancel under standard assumptions. Mutual information can then define a finite, regulator-independent correlation quantity.

This statement is not automatic when the regions touch. As the separation tends to zero, short-distance correlations can make the mutual information diverge.

Gauge constraints can obstruct a naive tensor factorization of the physical Hilbert space. Different choices of regional operator algebra, centers, edge modes, or extended Hilbert space can alter entropy assignments. State the algebraic prescription before comparing values.

The dedicated Entanglement in QFT Preview develops these issues without importing continuum formulas into a lattice calculation by analogy alone.

For an initial product state of finite-dimensional sites and bounded finite-range interactions, Lieb–Robinson locality constrains correlations created between fixed finite regions. Operators evolved for time tt can be approximated within neighborhoods of radius vLRtv_{\mathrm{LR}}t. Before these neighborhoods overlap, their expectation values factorize in the initial product state, up to the locality tails.

For regions separated by rr, the resulting correlation scale involves

r−2vLRt.r-2v_{\mathrm{LR}}t.

Controlling a complete operator basis on the finite regions then bounds the reduced-state distance from a product; entropy continuity converts that estimate to a mutual-information bound. The prefactors depend on region size and Hilbert-space dimension. One cannot infer a dimension-independent mutual-information estimate from a few two-point correlators.

Small initial I(A:B)I(A:B) alone is not enough. A remote system may already be entangled with a site next to AA; a local swap can move that existing correlation into AA before a new signal could travel from BB. For initially correlated states, one must also control correlations between enlarged neighborhoods. The Lieb–Robinson bound states the locality assumptions, while operator entanglement and scrambling distinguishes information spreading from transport.

For a state represented explicitly:

  1. trace out CC to obtain ρAB\rho_{AB};
  2. trace BB and AA to obtain ρA\rho_A and ρB\rho_B;
  3. diagonalize all three reduced operators;
  4. compute their entropies with one logarithm convention;
  5. form I(A:B)I(A:B) only after checking normalization and positivity.

The Hilbert-space cost grows exponentially with ∣A∪B∣|A\cup B|. Exploit exact symmetries without dropping sector probabilities from the entropy.

For a pure MPS and one contiguous complementary cut, I(A:Aˉ)=2SAI(A:\bar A)=2S_A follows from the bond Schmidt values. For disjoint regions or a mixed matrix-product operator, one needs the reduced operator on A∪BA\cup B as well as its marginals.

Convergence should be tested against:

  • bond dimension;
  • discarded weight;
  • system size and boundary conditions;
  • region size and separation;
  • purification or operator-space truncation at finite temperature.

An entropy that appears converged does not guarantee that the smaller difference I(A:B)I(A:B) is converged.

Replica or swap-operator methods naturally estimate integer-order Rényi entropies. One may form a quantity such as

Icomb(2)(A:B):=S2(A)+S2(B)−S2(AB).I^{(2)}_{\mathrm{comb}}(A:B) :=S_2(A)+S_2(B) {}-S_2(AB).

This is experimentally and numerically useful, but it is not the von Neumann mutual information. For Rényi index α≠1\alpha\ne1, several inequivalent generalizations exist, and the simple entropy combination need not inherit every property of I(A:B)I(A:B), including the same data-processing and positivity guarantees in full generality.

Report the definition, replica geometry, estimator, and normalization rather than writing an unqualified I(A:B)I(A:B).

For a concrete purity check, take two spins in the diagonal state

ρAB=diag⁡ ⁣(12,14,14,0)\rho_{AB}=\operatorname{diag}\!\left(\frac12,\frac14,\frac14,0\right)

in the ordered basis ∣00⟩,∣01⟩,∣10⟩,∣11⟩|00\rangle,|01\rangle,|10\rangle,|11\rangle. Both marginals are diag⁡(3/4,1/4)\operatorname{diag}(3/4,1/4). Their purities are 5/85/8, while the joint purity is 3/83/8, giving

Icomb(2)=ln⁡Tr⁡ρAB2Tr⁡ρA2 Tr⁡ρB2=ln⁡2425<0.I^{(2)}_{\mathrm{comb}} =\ln\frac{\operatorname{Tr}\rho_{AB}^2} {\operatorname{Tr}\rho_A^2\,\operatorname{Tr}\rho_B^2} =\ln\frac{24}{25}<0.

The same state has positive von Neumann mutual information,

I(A:B)=2h2(1/4)−32ln⁡2≃0.08495,h2(p)=−pln⁡p−(1−p)ln⁡(1−p).I(A:B)=2h_2(1/4)-\frac32\ln2 \simeq0.08495, \qquad h_2(p)=-p\ln p-(1-p)\ln(1-p).

It is a separable mixture of product basis states with classical correlations. A negative value of the measured purity combination alone therefore does not diagnose an invalid state or numerical error. Its definition differs from the nonnegative von Neumann quantity.

Interference between two copies can measure purities and second Rényi entropies. Randomized measurements provide another route to moments of reduced density operators. Both can construct Rényi correlation diagnostics for selected regions.

Experimental claims should report:

  • which Rényi index was measured;
  • state-preparation and detection errors;
  • symmetry or postselection constraints;
  • statistical covariance among the three entropy estimates;
  • whether the inferred quantity is total correlation or an entanglement witness.

Suppose estimates obey

S^X=SX+εX,X∈{A,B,AB}.\widehat S_X = S_X+\varepsilon_X, \qquad X\in\{A,B,AB\}.

Then

I^−I=εA+εB−εAB.\widehat I-I = \varepsilon_A + \varepsilon_B - \varepsilon_{AB}.

If the errors are independent with standard deviations σX\sigma_X,

σI2=σA2+σB2+σAB2.\sigma_I^2 = \sigma_A^2 + \sigma_B^2 + \sigma_{AB}^2.

For correlated estimates, the full expression is

σI2=σA2+σB2+σAB2+2Cov⁡(εA,εB)−2Cov⁡(εA,εAB)−2Cov⁡(εB,εAB).\sigma_I^2={}\sigma_A^2+\sigma_B^2+\sigma_{AB}^2 +2\operatorname{Cov}(\varepsilon_A,\varepsilon_B) -2\operatorname{Cov}(\varepsilon_A,\varepsilon_{AB}) -2\operatorname{Cov}(\varepsilon_B,\varepsilon_{AB}).

Because II may be an area-sized remainder of volume-sized entropies, absolute rather than relative entropy errors control reliability.

Let ∣Ψ⟩AB\lvert\Psi\rangle_{AB} be pure. Derive I(A:B)=2SAI(A:B)=2S_A and evaluate the mutual information for one Bell pair using natural logarithms.

Solution

Purity gives

SAB=0S_{AB}=0

and equality of the reduced spectra gives

SA=SB.S_A=S_B.

Therefore

I(A:B)=SA+SB−SAB=2SA.I(A:B) = S_A+S_B-S_{AB} = 2S_A.

For one Bell pair,

ρA=ρB=I2,\rho_A=\rho_B=\frac{I}{2},

so

SA=SB=ln⁡2.S_A=S_B=\ln2.

Hence

I(A:B)=2ln⁡2.I(A:B)=2\ln2.

For

H=−Jσ1zσ2z,H=-J\sigma_1^z\sigma_2^z,

derive

I(1:2)=xtanh⁡x−ln⁡cosh⁡x,x=βJ.\begin{aligned} I(1:2)&=x\tanh x-\ln\cosh x, \\ x&=\beta J. \end{aligned}

Explain why the result does not certify entanglement.

Solution

The partition function is

Z=4cosh⁡x.Z=4\cosh x.

Each one-spin marginal is I/2I/2, so

S1=S2=ln⁡2.S_1=S_2=\ln2.

The thermal entropy satisfies

S12=β⟨H⟩+ln⁡Z.S_{12} = \beta\langle H\rangle+\ln Z.

Since

⟨H⟩=−Jtanh⁡x,\langle H\rangle = -J\tanh x,

we obtain

S12=−xtanh⁡x+ln⁡(4cosh⁡x).S_{12} = -x\tanh x + \ln(4\cosh x).

Therefore

I(1:2)=2ln⁡2−S12=xtanh⁡x−ln⁡cosh⁡x.\begin{aligned} I(1:2) &= 2\ln2-S_{12} \\ &= x\tanh x-\ln\cosh x. \end{aligned}

The Gibbs state is diagonal in a product basis and is a classical mixture of product states. Its mutual information measures classical alignment correlation, not entanglement.

Two normalized observables satisfy

∥OA∥=∥OB∥=1\|O_A\|=\|O_B\|=1

and have connected correlator magnitude ∣CAB∣=0.30|C_{AB}|=0.30. What lower bound on I(A:B)I(A:B) follows in nats?

Solution

The Pinsker-based bound gives

I(A:B)≥∣CAB∣22.I(A:B) \ge \frac{|C_{AB}|^2}{2}.

Thus

I(A:B)≥0.3022=0.045.I(A:B) \ge \frac{0.30^2}{2} = 0.045.

This is only a lower bound. Other operator channels may carry additional correlation.

For ∣GHZN⟩\lvert\mathrm{GHZ}_N\rangle, compare:

  1. two nonempty disjoint regions AA and BB with a nonempty environment CC;
  2. a complementary cut B=AˉB=\bar A.
Solution

Every nonempty proper region has reduced state

ρX=12∣0⋯0⟩⟨0⋯0∣+12∣1⋯1⟩⟨1⋯1∣,\rho_X = \frac12 \lvert0\cdots0\rangle\langle0\cdots0\rvert + \frac12 \lvert1\cdots1\rangle\langle1\cdots1\rvert,

so SX=ln⁡2S_X=\ln2.

With nonempty CC, the union ABAB is also a proper region. Hence

I(A:B)=ln⁡2+ln⁡2−ln⁡2=ln⁡2.I(A:B) = \ln2+\ln2-\ln2 = \ln2.

For a complementary cut, the global state on ABAB is pure, so SAB=0S_{AB}=0 and

I(A:Aˉ)=2ln⁡2.I(A:\bar A)=2\ln2.

Tracing the environment removes the global coherence from ρAB\rho_{AB} while retaining one shared classical branch label.

For complementary regions in the full-space Gibbs state at β>0\beta>0, suppose H∂H_\partial is a sum of N∂N_\partial terms, each with norm at most JJ. Derive a thermal mutual-information bound. Explain why projecting to fixed total charge changes its assumptions.

Solution

The triangle inequality gives

∥H∂∥≤N∂J.\|H_\partial\| \le N_\partial J.

Insert this into the Gibbs-state bound:

I(A:B)≤2β∥H∂∥≤2βJN∂.I(A:B) \le 2\beta\|H_\partial\| \le 2\beta JN_\partial.

For finite-range lattice interactions, N∂N_\partial scales with the number of interaction edges crossing the boundary. The result is an area-law upper bound, not an equality or a prediction of the coefficient. In a projected charge sector, ρA⊗ρB\rho_A\otimes\rho_B is generally not a permissible trial state. The derivation must therefore be reconsidered rather than applied with the same H∂H_\partial.

For the uniformly mixed one-particle state on LL sites, show directly that a spatial partition with fraction f=LA/Lf=L_A/L has

I(A:B)=H2(f).I(A:B)=H_2(f).

What does the result become at f=1/2f=1/2?

Solution

The reduced state on AA has vacuum probability 1−f1-f and LAL_A one-particle eigenvalues equal to 1/L1/L. Therefore

SA=−(1−f)ln⁡(1−f)−LALln⁡1L.S_A = -(1-f)\ln(1-f) - \frac{L_A}{L}\ln\frac1L.

Using LA=fLL_A=fL,

SA=H2(f)+fln⁡LA.S_A = H_2(f)+f\ln L_A.

Similarly,

SB=H2(f)+(1−f)ln⁡LB.S_B = H_2(f)+(1-f)\ln L_B.

The full state has LL equal eigenvalues, so SAB=ln⁡LS_{AB}=\ln L. Substitution and LA=fLL_A=fL, LB=(1−f)LL_B=(1-f)L give

I(A:B)=H2(f).I(A:B)=H_2(f).

At half partition,

I(A:B)=ln⁡2.I(A:B)=\ln2.

The value records perfect anticorrelation of the regional particle-number indicators.

Three independently estimated entropies have standard deviations

σA=0.03,σB=0.04,σAB=0.05.\begin{aligned} \sigma_A&=0.03, &\sigma_B&=0.04, \\ \sigma_{AB}&=0.05. \end{aligned}

Find the standard deviation of the mutual-information estimator. Why would the answer change for correlated estimates?

Solution

For independent errors,

σI=σA2+σB2+σAB2=0.032+0.042+0.052=0.005≈0.0707.\begin{aligned} \sigma_I &= \sqrt{ \sigma_A^2+\sigma_B^2+\sigma_{AB}^2 } \\ &= \sqrt{0.03^2+0.04^2+0.05^2} \\ &= \sqrt{0.005} \approx 0.0707. \end{aligned}

If the estimates share samples, replicas, or calibration parameters, their errors have nonzero covariance. Then

Var⁡(εA+εB−εAB)\operatorname{Var} (\varepsilon_A+\varepsilon_B-\varepsilon_{AB})

contains cross terms whose signs depend on the subtraction. Ignoring them can either overestimate or underestimate the uncertainty.

Add white noise to the diagonal state in the replica example:

ρq=(1−q)I44+q diag⁡ ⁣(12,14,14,0),0≤q≤1.\rho_q=(1-q)\frac{I_4}{4} +q\,\operatorname{diag}\!\left(\frac12,\frac14,\frac14,0\right), \qquad 0\le q\le1.

Compute the two local purities and the joint purity. Does Icomb(2)I^{(2)}_{\mathrm{comb}} become nonnegative at some nonzero noise fraction? Determine whether the states are entangled and when their von Neumann mutual information vanishes.

Solution

The joint probabilities are ((1+q)/4,1/4,1/4,(1−q)/4)((1+q)/4,1/4,1/4,(1-q)/4), and each marginal has probabilities (1/2+q/4,1/2−q/4)(1/2+q/4,1/2-q/4). Consequently,

Tr⁡ρq,A2=Tr⁡ρq,B2=4+q28,Tr⁡ρq2=2+q28.\operatorname{Tr}\rho_{q,A}^2 =\operatorname{Tr}\rho_{q,B}^2=\frac{4+q^2}{8}, \qquad \operatorname{Tr}\rho_q^2=\frac{2+q^2}{8}.

The combination is

Icomb(2)=ln⁡8(2+q2)(4+q2)2.I^{(2)}_{\mathrm{comb}} =\ln\frac{8(2+q^2)}{(4+q^2)^2}.

The denominator exceeds the numerator by q4q^4, so the result is negative for every q>0q>0 and zero at q=0q=0. The effect survives any white-noise fraction short of complete mixing, although its magnitude tends to zero and must be compared with measurement uncertainty.

Every ρq\rho_q is diagonal in a product basis with nonnegative probabilities, so all are separable. The determinant of their 2×22\times2 joint probability table is −q2/16-q^2/16; the distribution factorizes only at q=0q=0. Thus the von Neumann mutual information is positive for q>0q>0 and zero only at q=0q=0. This family has classical correlations without entanglement throughout the nonzero-qq range.