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Adiabatic elimination replaces rapidly evolving or weakly populated quantum degrees of freedom by their approximate response to slow ones. The eliminated variables do not simply disappear: virtual excursions through them shift energies, induce couplings, and, in open systems, generate effective decay and dephasing.

The familiar instruction “set the fast derivative to zero” is useful only when read as the leading term of a slow–fast expansion. An exact elimination produces a transient and a memory kernel. A local effective Hamiltonian appears after showing that the slow state and the couplings change little over the fast response time.

Required background. Projection methods introduces the block decomposition, error estimates explains the scale ratios, and the interaction picture supplies the rotating-frame construction. Unlike the adiabatic theorem, elimination does not require following one slowly varying instantaneous eigenstate.

Set ℏ=1\hbar=1 in the closed-system derivation; restore it in the atomic example. Split a state into slow and fast components,

∣Ψ(t)⟩=(ψs(t)ψf(t)),\lvert\Psi(t)\rangle = \begin{pmatrix} \psi_s(t)\\ \psi_f(t) \end{pmatrix},

and write the Schrödinger equation in block form:

iddt(ψsψf)=(ABCD)(ψsψf).i\frac{d}{dt} \begin{pmatrix} \psi_s\\ \psi_f \end{pmatrix} = \begin{pmatrix} A & B\\ C & D \end{pmatrix} \begin{pmatrix} \psi_s\\ \psi_f \end{pmatrix}.

Thus

iψ˙s=Aψs+Bψf,iψ˙f=Cψs+Dψf.\begin{aligned} i\dot\psi_s &= A\psi_s+B\psi_f, \\ i\dot\psi_f &= C\psi_s+D\psi_f. \end{aligned}

Here AA and DD generate motion within the slow and fast sectors, while BB and CC transfer amplitude between them. For a Hermitian Hamiltonian,

A†=A,D†=D,C=B†.A^\dagger=A, \qquad D^\dagger=D, \qquad C=B^\dagger.

“Fast” is a statement about frequencies in a chosen frame, not about a label attached to a basis state. After removing a convenient reference energy, the spectrum of DD should be far from the frequencies resolved by ψs\psi_s. A large common energy added to both blocks has no dynamical significance and does not create scale separation.

Two common mechanisms make a sector fast:

  • Large detuning: eigenfrequencies in DD lie far from the slow band.
  • Rapid relaxation: eigenmodes in the fast sector decay on a timescale short compared with the retained dynamics.

The second case requires an open-system description; it cannot generally be represented by a Hermitian Hamiltonian alone.

Let Uf(t,t′)U_f(t,t') be the propagator generated by D(t)D(t):

i∂∂tUf(t,t′)=D(t)Uf(t,t′),Uf(t′,t′)=If.\begin{aligned} i\frac{\partial}{\partial t}U_f(t,t') &= D(t)U_f(t,t'), \\ U_f(t',t') &= I_f. \end{aligned}

Variation of constants gives the exact fast amplitude

ψf(t)=Uf(t,t0)ψf(t0)−i∫t0tUf(t,t′)C(t′)ψs(t′) dt′.\psi_f(t) = U_f(t,t_0)\psi_f(t_0) -i\int_{t_0}^{t} U_f(t,t') C(t')\psi_s(t')\,dt'.

Substitution into the slow equation yields

iψ˙s(t)=A(t)ψs(t)+B(t)Uf(t,t0)ψf(t0)−iB(t)∫t0tdt′ Uf(t,t′)×C(t′)ψs(t′).i\dot\psi_s(t) = A(t)\psi_s(t) + B(t)U_f(t,t_0)\psi_f(t_0) -iB(t) \int_{t_0}^{t}dt'\, U_f(t,t') \times C(t')\psi_s(t').

This identity separates two effects:

  • The term containing ψf(t0)\psi_f(t_0) is an initial transient. It retains knowledge of any fast-sector population present at the starting time.
  • The integral is a memory term. The present slow derivative depends on the slow state at earlier times.

Adiabatic elimination is the approximation that turns this nonlocal equation into a local one. It is justified when the kernel Uf(t,t′)U_f(t,t') oscillates or decays before ψs(t′)\psi_s(t') and the couplings change appreciably.

For constant DD,

Uf(t,t′)=e−iD(t−t′).U_f(t,t') = e^{-iD(t-t')}.

For a finite closed fast sector, e−iD(t−t′)e^{-iD(t-t')} oscillates but does not decay. Integration by parts isolates a slowly varying particular solution and an endpoint oscillation. For constant invertible D,CD,C, to leading derivative order,

ψf(t)≃−D−1Cψs(t)+e−iD(t−t0)[ψf(t0)+D−1Cψs(t0)].\psi_f(t)\simeq{}-D^{-1}C\psi_s(t) +e^{-iD(t-t_0)}\bigl[\psi_f(t_0)+D^{-1}C\psi_s(t_0)\bigr].

The oscillation is present even if the bare fast amplitude initially vanishes. Preparing a dressed slow state suppresses it; coarse graining can hide it in selected observables but does not make it vanish microscopically. A genuinely decaying fast propagator can instead erase the initial term after its relaxation time. These alternatives must not be conflated with an automatic loss of memory in a finite closed system.

The rough prescription sets the fast derivative to zero:

iψ˙f≃0.i\dot\psi_f \simeq 0.

If DD is invertible, the fast amplitude is then slaved to the slow one:

ψf≃−D−1Cψs.\psi_f \simeq - D^{-1}C\psi_s.

The slow equation becomes

iψ˙s≃Heff(0)ψs,i\dot\psi_s \simeq H_{\mathrm{eff}}^{(0)}\psi_s,

with

Heff(0)=A−BD−1C.H_{\mathrm{eff}}^{(0)} = A-BD^{-1}C.

The correction has a simple path interpretation:

s→ C f→ −D−1 f→ B s.s \xrightarrow{\,C\,} f \xrightarrow{\,-D^{-1}\,} f \xrightarrow{\,B\,} s.

It shifts retained levels and can connect two slow states that had no direct matrix element in AA. For a Hermitian problem with C=B†C=B^\dagger, the leading Hamiltonian is Hermitian.

This expression is the zero-frequency Schur complement. It agrees with the leading stationary projection and Schrieffer–Wolff results when all methods use the same frame, model space, and perturbative order. Their higher-order state and observable conventions need not be identical.

The reconstructed fast population scales as

∥ψf∥2≲∥D−1C∥2∥ψs∥2.\lVert\psi_f\rVert^2 \lesssim \lVert D^{-1}C\rVert^2 \lVert\psi_s\rVert^2.

Small fast population therefore requires ∥D−1C∥≪1\lVert D^{-1}C\rVert\ll1. It does not imply a negligible effect on slow phases: a correction of order g2/Δg^2/\Delta can accumulate coherently for times of order Δ/g2\Delta/g^2.

For time-independent DD and CC, discard the homogeneous transient and formally solve

ψf=−(D−i∂t)−1Cψs.\psi_f = - \left( D-i\partial_t \right)^{-1} C\psi_s.

On slow, bandwidth-limited states, expand the inverse:

ψf=−D−1Cψs−iD−2Cψ˙s+D−3Cψ¨s+⋯ .\psi_f = - D^{-1}C\psi_s -iD^{-2}C\dot\psi_s + D^{-3}C\ddot\psi_s +\cdots.

The algebraic substitution is the first term. Keeping the first derivative gives

Ns=Is+BD−2C,iNsψ˙s=(A−BD−1C)ψs+higher derivatives.\begin{aligned} N_s &= I_s+BD^{-2}C ,\\ iN_s\dot\psi_s &= \left( A-BD^{-1}C \right)\psi_s + \text{higher derivatives}. \end{aligned}

The matrix multiplying ψ˙s\dot\psi_s is a reminder that the projected slow amplitude is not yet the fully normalized dressed state. In the Hermitian case, define

N=Is+BD−2B†,χ=N1/2ψs.\begin{aligned} N &= I_s+BD^{-2}B^\dagger, \\ \chi &= N^{1/2}\psi_s. \end{aligned}

To this order,

∥Ψ∥2≃⟨ψs∣N∣ψs⟩=∥χ∥2.\lVert\Psi\rVert^2 \simeq \langle\psi_s\rvert N\lvert\psi_s\rangle = \lVert\chi\rVert^2.

For constant blocks, a standard Hermitian generator for χ\chi is

Heff(1)=N−1/2(A−BD−1B†)N−1/2,H_{\mathrm{eff}}^{(1)} = N^{-1/2} \left( A-BD^{-1}B^\dagger \right) N^{-1/2},

up to the order retained in the derivative expansion. This normalization step explains why an unsymmetrized higher-order substitution can appear non-Hermitian even when the full Hamiltonian is Hermitian.

If BB, CC, or DD depends on time, derivatives also act on those operators and their order matters. In that setting, either derive the local series from the exact propagator or use a systematic time-dependent block transformation. Blindly replacing every fast derivative by zero can miss ramp-induced terms.

For a finite-dimensional Hermitian fast block measured relative to the slow reference frequency, define

Δf=∥D−1∥−1.\Delta_f = \lVert D^{-1}\rVert^{-1}.

This is the distance to the closest dangerous fast-sector frequency. Let gg bound the coupling blocks, let ωs\omega_s characterize the retained bandwidth, and let τramp\tau_{\mathrm{ramp}} be the shortest timescale on which the blocks change. Useful diagnostics are

ϵc=gΔf,ϵs=ωsΔf,ϵr=1Δfτramp.\begin{aligned} \epsilon_c &= \frac{g}{\Delta_f}, \\ \epsilon_s &= \frac{\omega_s}{\Delta_f}, \\ \epsilon_r &= \frac{1} {\Delta_f\tau_{\mathrm{ramp}}}. \end{aligned}

Leading adiabatic elimination requires all relevant ratios to be small. A responsible calculation checks more than one denominator:

  1. Spectral or decay separation: the fast response time must be short compared with retained motion.
  2. Weak occupation: ∥D−1C∥≪1\lVert D^{-1}C\rVert\ll1 for states in the retained sector.
  3. Slow envelopes: drives and control parameters should not change appreciably during the fast response time.
  4. Compatible initial data: fast transients must be absent, irrelevant after coarse graining, or included explicitly.
  5. No hidden resonance: a near-resonant fast eigenstate belongs in the retained space.
  6. Controlled time window: if the neglected generator is δH\delta H, require ∥δH∥t≪1\lVert\delta H\rVert t\ll1 for phase-sensitive predictions.
  7. Observable consistency: leakage and fast-sector observables require state reconstruction, not only HeffH_{\mathrm{eff}}.

For a non-normal fast generator, eigenvalue distance alone can be misleading. The resolvent norm or pseudospectral response can be large even when every eigenvalue appears far away. In unbounded problems, domains and relative bounds require separate analysis.

The instruction ψ˙f≃0\dot\psi_f\simeq0 is not invariant under an arbitrary rapidly rotating change of picture. A poor frame can make a slow amplitude look fast or shift a large frequency into the wrong block. Choose a frame in which:

  • retained amplitudes vary on the physical slow scale;
  • the fast detunings or decay rates remain explicit in DD;
  • the couplings have slowly varying envelopes.

Interaction Picture and Rotating-Wave Approximation develop the transformations often used before elimination. The rotating-wave approximation removes rapidly oscillating Hamiltonian terms; adiabatic elimination removes a fast dynamical variable. One does not automatically imply the other.

Consider two long-lived states ∣g1⟩\lvert g_1\rangle and ∣g2⟩\lvert g_2\rangle coupled to an excited state ∣e⟩\lvert e\rangle. In a rotating frame, after any rotating-wave approximation has been justified, take

Hℏ=δ∣g2⟩⟨g2∣+Δ∣e⟩⟨e∣+12(Ω1∣e⟩⟨g1∣+Ω2∣e⟩⟨g2∣+h.c.).\frac{H}{\hbar} = \delta \lvert g_2\rangle\langle g_2\rvert + \Delta \lvert e\rangle\langle e\rvert + \frac{1}{2} \left( \Omega_1 \lvert e\rangle\langle g_1\rvert + \Omega_2 \lvert e\rangle\langle g_2\rvert + \mathrm{h.c.} \right).

Here Δ\Delta is the one-photon detuning and δ\delta is the two-photon detuning in this convention.

A detuned three-level Lambda system reduced to an effective two-level ground-state manifold with a Raman coupling and ac Stark shifts.

When ∣Δ∣\lvert\Delta\rvert dominates the Rabi frequencies and slow ground-manifold scales, the excited amplitude is weak and fast. Eliminating ∣e⟩\lvert e\rangle leaves a Raman coupling between ∣g1⟩\lvert g_1\rangle and ∣g2⟩\lvert g_2\rangle together with state-dependent ac Stark shifts.

For

∣Ψ⟩=c1∣g1⟩+c2∣g2⟩+ce∣e⟩,\lvert\Psi\rangle = c_1\lvert g_1\rangle + c_2\lvert g_2\rangle + c_e\lvert e\rangle,

the amplitude equations are

ic˙1=Ω1∗2ce,ic˙2=δc2+Ω2∗2ce,ic˙e=Δce+Ω1c1+Ω2c22.\begin{aligned} i\dot c_1 &= \frac{\Omega_1^*}{2}c_e, \\ i\dot c_2 &= \delta c_2 + \frac{\Omega_2^*}{2}c_e, \\ i\dot c_e &= \Delta c_e + \frac{\Omega_1c_1+\Omega_2c_2}{2}. \end{aligned}

If

∣Ω1∣,∣Ω2∣,∣δ∣≪∣Δ∣,\lvert\Omega_1\rvert, \lvert\Omega_2\rvert, \lvert\delta\rvert \ll \lvert\Delta\rvert,

the leading fast response is

ce≃−Ω1c1+Ω2c22Δ.c_e \simeq - \frac{ \Omega_1c_1+\Omega_2c_2 } {2\Delta}.

Substitution gives the ground-manifold Hamiltonian

Heffℏ=(−∣Ω1∣24Δ−Ω1∗Ω24Δ−Ω2∗Ω14Δδ−∣Ω2∣24Δ).\frac{H_{\mathrm{eff}}}{\hbar} = \begin{pmatrix} -\dfrac{\lvert\Omega_1\rvert^2}{4\Delta} & -\dfrac{\Omega_1^*\Omega_2}{4\Delta} \\ -\dfrac{\Omega_2^*\Omega_1}{4\Delta} & \delta-\dfrac{\lvert\Omega_2\rvert^2}{4\Delta} \end{pmatrix}.

The diagonal terms are ac Stark shifts. Defining the effective two-state coupling by an off-diagonal matrix element ℏΩR/2\hbar\Omega_{\mathrm R}/2 gives

ΩR=−Ω1∗Ω22Δ.\Omega_{\mathrm R} = - \frac{\Omega_1^*\Omega_2} {2\Delta}.

The effective two-photon detuning is

δeff=δ−∣Ω2∣2−∣Ω1∣24Δ.\delta_{\mathrm{eff}} = \delta - \frac{ \lvert\Omega_2\rvert^2 - \lvert\Omega_1\rvert^2 } {4\Delta}.

Thus the Raman resonance is shifted by the differential ac Stark shift. Dropping the diagonal terms while keeping the Raman coupling is inconsistent because both arise at the same order.

For δ=0\delta=0, define

Ω=∣Ω1∣2+∣Ω2∣2.\Omega = \sqrt{ \lvert\Omega_1\rvert^2 + \lvert\Omega_2\rvert^2 }.

The normalized combinations

∣B⟩=Ω1∗∣g1⟩+Ω2∗∣g2⟩Ω,∣D⟩=Ω2∣g1⟩−Ω1∣g2⟩Ω\begin{aligned} \lvert B\rangle &= \frac{ \Omega_1^*\lvert g_1\rangle + \Omega_2^*\lvert g_2\rangle }{\Omega}, \\ \lvert D\rangle &= \frac{ \Omega_2\lvert g_1\rangle - \Omega_1\lvert g_2\rangle }{\Omega} \end{aligned}

are bright and dark, respectively. The excitation operator annihilates ∣D⟩\lvert D\rangle, while

Heff∣B⟩=−ℏΩ24Δ∣B⟩,Heff∣D⟩=0.\begin{aligned} H_{\mathrm{eff}}\lvert B\rangle &= - \frac{\hbar\Omega^2}{4\Delta} \lvert B\rangle, \\ H_{\mathrm{eff}}\lvert D\rangle &= 0. \end{aligned}

For the slowly varying dressed component, the leading excited-state population obeys

∣ce∣2≲Ω24Δ2.\lvert c_e\rvert^2 \lesssim \frac{\Omega^2}{4\Delta^2}.

An abruptly prepared bare bright state has an additional fast oscillation: its peak excited population is approximately Ω2/Δ2\Omega^2/\Delta^2, four times the dressed-state estimate. The dark state is exactly uncoupled for the ideal Hamiltonian, whereas the bright state acquires a virtual light shift. Time-dependent dark-state transport is a separate adiabatic-following problem; it should not be inferred from elimination alone.

Suppose the fast excited sector also decays. Begin with a Lindblad equation,

ρ˙=−iℏ[H,ρ]+∑kD[Lk]ρ,\dot\rho = - \frac{i}{\hbar}[H,\rho] + \sum_k \mathcal D[L_k]\rho,

where

D[L]ρ=LρL†−12{L†L,ρ}.\mathcal D[L]\rho = L\rho L^\dagger - \frac12 \left\{ L^\dagger L,\rho \right\}.

Write

H=Hg+He+V++V−,V−=V+†,H = H_g+H_e+V_++V_-, \qquad V_-=V_+^\dagger,

where V+V_+ excites the slow sector into the fast one. If each LkL_k returns population from the excited sector to the ground sector, define the excited-sector non-Hermitian Hamiltonian

HNH=He−iℏ2∑kLk†Lk.H_{\mathrm{NH}} = H_e - \frac{i\hbar}{2} \sum_k L_k^\dagger L_k.

For weak excitation, fast relaxation compared with retained dynamics, and a bounded inverse fast response, the leading effective operators are (Reiter and Sørensen, 2012)

Heff=Hg−12V−[HNH−1+(HNH−1)†]V+,Leff(k)=LkHNH−1V+.\begin{aligned} H_{\mathrm{eff}} &= H_g - \frac12 V_- \left[ H_{\mathrm{NH}}^{-1} + \left( H_{\mathrm{NH}}^{-1} \right)^\dagger \right] V_+, \\ L_{\mathrm{eff}}^{(k)} &= L_k H_{\mathrm{NH}}^{-1} V_+. \end{aligned}

Here the ground-state splittings and couplings must be small on the fast response scale in the chosen frame. Large retained splittings require energy-resolved denominators or the generalized effective-operator construction; invertibility alone does not justify the displayed approximation. These operators generate a trace-preserving effective master equation entirely in the retained sector:

ρ˙g=−iℏ[Heff,ρg]+∑kD[Leff(k)]ρg.\dot\rho_g = - \frac{i}{\hbar} [H_{\mathrm{eff}},\rho_g] + \sum_k \mathcal D \left[ L_{\mathrm{eff}}^{(k)} \right]\rho_g.

The sequence encoded by an effective jump is

g→ V+ e→ HNH−1 e→ Lk g.g \xrightarrow{\,V_+\,} e \xrightarrow{\,H_{\mathrm{NH}}^{-1}\,} e \xrightarrow{\,L_k\,} g.

For one excited state with detuning Δ\Delta and total linewidth Γ\Gamma,

HNH=ℏ(Δ−iΓ2)∣e⟩⟨e∣.H_{\mathrm{NH}} = \hbar \left( \Delta-\frac{i\Gamma}{2} \right) \lvert e\rangle\langle e\rvert.

A weak Rabi coupling Ω\Omega then produces an effective scattering scale

Γsc∼Γ∣Ω∣24[Δ2+(Γ/2)2].\Gamma_{\mathrm{sc}} \sim \frac{ \Gamma\lvert\Omega\rvert^2 } { 4\left[ \Delta^2+(\Gamma/2)^2 \right] }.

Replacing Δ\Delta by Δ−iΓ/2\Delta-i\Gamma/2 in a Hamiltonian but omitting the effective jumps describes only no-jump loss. It does not preserve trace and generally misses where the emitted population goes. Lindblad–GKSL Equation explains the master-equation structure, while Quantum-Jump Trajectories develops its conditional interpretation.

1. Derive an effective scattering operator

Section titled “1. Derive an effective scattering operator”

A ground state ∣g⟩\lvert g\rangle couples to a decaying excited state ∣e⟩\lvert e\rangle with

V+=ℏΩ2∣e⟩⟨g∣,L=Γ∣g⟩⟨e∣.\begin{aligned} V_+ &= \frac{\hbar\Omega}{2} \lvert e\rangle\langle g\rvert, \\ L &= \sqrt{\Gamma} \lvert g\rangle\langle e\rvert. \end{aligned}

Use HNH=ℏ(Δ−iΓ/2)∣e⟩⟨e∣H_{\mathrm{NH}}=\hbar(\Delta-i\Gamma/2)\lvert e\rangle\langle e\rvert to find LeffL_{\mathrm{eff}} and its rate scale.

Solution

The inverse fast propagator is

HNH−1=∣e⟩⟨e∣ℏ(Δ−iΓ/2).H_{\mathrm{NH}}^{-1} = \frac{ \lvert e\rangle\langle e\rvert } {\hbar(\Delta-i\Gamma/2)}.

Therefore

Leff=Γ Ω2(Δ−iΓ/2)∣g⟩⟨g∣.L_{\mathrm{eff}} = \frac{ \sqrt{\Gamma}\,\Omega } {2(\Delta-i\Gamma/2)} \lvert g\rangle\langle g\rvert.

Its squared coefficient is

Γsc=Γ∣Ω∣24[Δ2+(Γ/2)2].\Gamma_{\mathrm{sc}} = \frac{ \Gamma\lvert\Omega\rvert^2 } { 4\left[ \Delta^2+(\Gamma/2)^2 \right] }.

If another ground state is unaffected by the drive, this projector-valued jump dephases superpositions relative to that state even though it returns population to ∣g⟩\lvert g\rangle.

2. Scattering without a change of the internal state

Section titled “2. Scattering without a change of the internal state”

For the jump Leff=γ∣g⟩⟨g∣L_{\mathrm{eff}}=\sqrt{\gamma}\lvert g\rangle\langle g\rvert, calculate the dissipator on ρ=∣g⟩⟨g∣\rho=\lvert g\rangle\langle g\rvert and, when an undriven state ∣u⟩\lvert u\rangle exists, on the coherence ρgu\rho_{gu}.

Solution

The dissipator vanishes on ∣g⟩⟨g∣\lvert g\rangle\langle g\rvert, although the mean photon count rate Tr⁡(L†Lρ)\operatorname{Tr}(L^\dagger L\rho) is γ\gamma. In the two-state retained manifold, ρ˙gu=−γρgu/2\dot\rho_{gu}=-\gamma\rho_{gu}/2. Emission can reveal which component was occupied and dephase a superposition while leaving each population unchanged. The scattering rate and the decay rate of a coherence are different observables.

In the constant two-state model H=(0ggΔ)H=\left(\begin{smallmatrix}0&g\\g&\Delta\end{smallmatrix}\right) with real gg and Δ>0\Delta>0, the retained eigenvalue is −g2/Δ+g4/Δ3+⋯-g^2/\Delta+g^4/\Delta^3+\cdots. For a dressed initial state, how long can the leading Hamiltonian predict its phase accurately?

Solution

With ℏ=1\hbar=1, the omitted phase is Tg4/Δ3Tg^4/\Delta^3. Requiring it to be much smaller than one gives T≪Δ3/g4T\ll\Delta^3/g^4. The eliminated population stays of order g2/Δ2g^2/\Delta^2 throughout. Small leakage therefore does not guarantee an accurate phase for arbitrarily long evolution. The stricter tolerance ε\varepsilon replaces the upper time scale by εΔ3/g4\varepsilon\Delta^3/g^4.