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Superselection in Algebraic Language

Algebraic superselection compares representations and states of one specified observable algebra. Central projections separate classical sector labels, while multiplicities and nontrivial commutants need not define distinct sectors. For infinite systems, quasi-equivalence and disjointness make these comparisons precise without requiring every representation to be a discrete sum of irreducibles.

Required background. Representations distinguishes equivalence and multiplicity. Superselection Rules explains the physical restriction of observables. Von Neumann Algebras supplies centers and normal states.

Central projections label observable sectors

Section titled “Central projections label observable sectors”

Let π\pi represent a unital C*-algebra A\mathcal A and set M=π(A)′′\mathcal M=\pi(\mathcal A)''. Its center is

Z(M)=M∩M′.Z(\mathcal M)=\mathcal M\cap\mathcal M'.

A central projection zz splits both the Hilbert space and the represented algebra into mutually reducing pieces. Every observable in M\mathcal M is block diagonal with respect to zz and I−zI-z.

For a normal state ω\omega, the numbers ω(z)\omega(z) are probabilities of central events. If 0<p=ω(z)<10<p=\omega(z)<1, the conditional functionals

ωz(A)=ω(zA)p,ω1−z(A)=ω((I−z)A)1−p\omega_z(A)=\frac{\omega(zA)}p,\qquad \omega_{1-z}(A)=\frac{\omega((I-z)A)}{1-p}

are positive normalized states, because centrality makes zAzA positive whenever AA is positive. They reconstruct ω\omega as a convex combination.

The center is therefore a commutative algebra of classical decomposition data. A factor has center CI\mathbb CI, so no nontrivial central event splits it. It can nevertheless act reducibly and support mixed states.

A finite-dimensional model separates weights from internal states

Section titled “A finite-dimensional model separates weights from internal states”

Consider the observable algebra

A=M2(C)⊕M3(C).\mathcal A=M_2(\mathbb C)\oplus M_3(\mathbb C).

Every state has the form

ω(A⊕B)=p Tr⁡(ρ2A)+(1−p)Tr⁡(ρ3B),\omega(A\oplus B) =p\,\operatorname{Tr}(\rho_2A) +(1-p)\operatorname{Tr}(\rho_3B),

where 0≤p≤10\leq p\leq1 and each density matrix is normalized when its coefficient is nonzero. The central projections I2⊕0I_2\oplus0 and 0⊕I30\oplus I_3 determine the weight pp.

This formula distinguishes classical uncertainty about the summand from mixedness inside a summand. For 0<p<10<p<1, the state is not pure even if both conditional density matrices are rank one. A pure state occupies one summand and is pure there.

Calling these summands physical superselection sectors assumes that this is the observable algebra of the system. Embedding it into M5M_5 introduces additional off-diagonal observables and changes which preparations are distinguishable. Algebra alone does not justify why those larger-algebra observables are physically excluded.

Equivalent copies are multiplicity, not central labels

Section titled “Equivalent copies are multiplicity, not central labels”

Represent M2M_2 on C2⊗Cr\mathbb C^2\otimes\mathbb C^r by A↦A⊗IrA\mapsto A\otimes I_r. The commutant is I2⊗MrI_2\otimes M_r, but the represented algebra’s center remains scalar. A projection selecting one multiplicity vector lies in the commutant and generally not in the represented algebra.

Consequently different copies are not central observable sectors. This is the same distinction between irreducible type and copy that appears in compact-group decompositions, now applied to the observable representation itself.

The example also shows why a nontrivial commutant alone does not establish physically distinct superselection sectors. One must identify central projections that distinguish observable alternatives or a physically justified class of inequivalent representations.

Normal state families define quasi-equivalence

Section titled “Normal state families define quasi-equivalence”

The folium of a representation π\pi is the set of state functionals on A\mathcal A obtained by restricting normal states of π(A)′′\pi(\mathcal A)''. Concretely, they can be written using density operators on the representation Hilbert space:

a⟼Tr⁡(ρ π(a)).a\longmapsto\operatorname{Tr}(\rho\,\pi(a)).

Different densities can give the same restricted functional.

Two representations are quasi-equivalent when their von Neumann closures are normally star-isomorphic by a map carrying π1(a)\pi_1(a) to π2(a)\pi_2(a) for every aa. The quasi-equivalence theorem (Bratteli and Robinson, Section 2.4.4) makes this equivalent to equality of their folia. This theorem is imported, not inferred merely from abstract algebra isomorphism.

One copy and several identical copies of the defining representation of MnM_n are quasi-equivalent: they admit exactly the same algebraic state functionals. They are not unitarily equivalent when their multiplicities differ. Quasi-equivalence removes this spectator multiplicity from the comparison.

Disjointness is stronger than inequivalence

Section titled “Disjointness is stronger than inequivalence”

Representations are disjoint when they have no unitarily equivalent nonzero subrepresentations. Equivalently, there is no nonzero bounded intertwiner between them. Distinct irreducible representations are disjoint if they are inequivalent, but this implication fails for reducible representations that share a common summand.

A direct sum of disjoint representations has separate central support projections in its von Neumann closure. By contrast, merely choosing two nonequivalent reducible representations does not guarantee such a split.

In general infinite systems, decomposition into factors may use direct integrals, and arbitrary representations need not have a manageable unique decomposition into irreducibles. Stronger sector classifications require extra assumptions, such as type-I structure or locality and a chosen physical selection criterion. Those conditions are additional theory, not consequences of the word “sector.”

Exercise: inequivalent but overlapping representations

Section titled “Exercise: inequivalent but overlapping representations”

Let πx\pi_x be point evaluation of C([0,1])C([0,1]) at xx. Are π0⊕π1\pi_0\oplus\pi_1 and π0⊕π1/2\pi_0\oplus\pi_{1/2} disjoint? Are they quasi-equivalent?

Solution

They are not disjoint because both contain π0\pi_0. They are not quasi-equivalent either: the first folium contains the state f↦f(1)f\mapsto f(1), whereas every state in the second folium is supported on {0,1/2}\{0,1/2\}. Thus neither unitary inequivalence nor failure of quasi-equivalence by itself implies disjointness.

  • Bratteli, Ola, and Derek W. Robinson, Operator Algebras and Quantum Statistical Mechanics 1, 2nd ed., Springer, 1987, doi:10.1007/978-3-662-02520-8, Section 2.4.4 — quasi-equivalence and disjointness; Section 4.2.2 — central and subcentral decompositions.
  • Naaijkens, Pieter, Quantum Spin Systems on Infinite Lattices, Lecture Notes in Physics 933, Springer, 2017, arXiv:1311.2717 — representations and sector questions for infinite quantum systems.