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Direct Sums and Superselection

A direct sum separates mutually orthogonal alternatives inside a Hilbert space. It becomes a superselection decomposition only when the admitted observable algebra cannot connect the alternatives. Under that restriction, phases between sectors have no observable effect, and a vector with several nonzero sector components induces a mixed state on the restricted algebra. This page proves that elementary finite or countable sector statement; physical origins and symmetry-specific sector rules are treated separately in Superselection Sectors.

Required background. Physical States as Rays separates rays from representatives. Expectation Functionals explains why specifying the observable algebra is part of specifying a state.

For Hilbert spaces Hα\mathcal H_\alpha, with a finite or countable label set, the Hilbert direct sum consists of vectors

H=⨁αHα,ψ=(ψα)α,∑α∥ψα∥2<∞.\mathcal H=\bigoplus_\alpha\mathcal H_\alpha, \qquad \psi=(\psi_\alpha)_\alpha, \qquad \sum_\alpha\|\psi_\alpha\|^2<\infty.

Its inner product is ⟨ψ,ϕ⟩=∑α⟨ψα,ϕα⟩\langle\psi,\phi\rangle=\sum_\alpha\langle\psi_\alpha,\phi_\alpha\rangle. The orthogonal projection PαP_\alpha extracts one component, and the sum of these projections converges strongly to the identity. A direct sum describes alternatives; a tensor product describes simultaneous subsystem degrees of freedom. A sector decomposition is not, by itself, a bipartite decomposition.

There are many possible orthogonal decompositions of the same space. A qubit can be written as the direct sum of its two computational basis lines, yet ordinary qubit experiments measure σx\sigma_x and detect coherence between them. Direct-sum notation alone therefore establishes no superselection rule.

Consider the bounded algebra

A={⨁αAα:Aα∈B(Hα),sup⁡α∥Aα∥<∞}.\mathcal A= \left\{\bigoplus_\alpha A_\alpha: A_\alpha\in\mathcal B(\mathcal H_\alpha), \sup_\alpha\|A_\alpha\|<\infty\right\}.

Equivalently, every A∈AA\in\mathcal A commutes with every PαP_\alpha. The sector projections belong to the center of this algebra: they commute with all its elements. Thus the sector label is a classical alternative within this particular quantum description.

For a unit vector ψ\psi, let pα=∥ψα∥2p_\alpha=\|\psi_\alpha\|^2. When pα>0p_\alpha>0, define ψ^α=ψα/pα\widehat\psi_\alpha=\psi_\alpha/\sqrt{p_\alpha}. The block structure gives

⟨ψ,Aψ⟩=∑αpα⟨ψ^α,Aαψ^α⟩.\langle\psi,A\psi\rangle =\sum_\alpha p_\alpha \langle\widehat\psi_\alpha,A_\alpha\widehat\psi_\alpha\rangle.

Replacing ψα\psi_\alpha independently by eiθαψαe^{i\theta_\alpha}\psi_\alpha changes none of these expectations. More strongly, the vector projection PψP_\psi and the density operator

ρdiag=∑α:pα>0pα∣ψ^α⟩⟨ψ^α∣\rho_{\rm diag} =\sum_{\alpha:p_\alpha>0} p_\alpha|\widehat\psi_\alpha\rangle \langle\widehat\psi_\alpha|

define the same functional on A\mathcal A. In a countable sum the positive series converges in trace norm, since its tail trace is the remaining sector probability.

The equality is relative to A\mathcal A. On the full algebra B(H)\mathcal B(\mathcal H), PψP_\psi is still pure, and off-diagonal operators can distinguish it from ρdiag\rho_{\rm diag}. If two or more sector weights are nonzero, the restriction to A\mathcal A is a nontrivial convex mixture of sector-supported functionals. It is consequently mixed on that algebra.

Take H=C⊕C\mathcal H=\mathbb C\oplus\mathbb C and restrict observables to diagonal matrices. The vectors

ψθ=p e0+eiθ1−p e1\psi_\theta=\sqrt p\,e_0 +e^{i\theta}\sqrt{1-p}\,e_1

all yield the same expectation pa+(1−p)bpa+(1-p)b for A=diag⁡(a,b)A=\operatorname{diag}(a,b). Their restricted state equals the classical distribution (p,1−p)(p,1-p).

If σx\sigma_x becomes an admitted observable, however,

⟨ψθ,σxψθ⟩=2p(1−p)cos⁡θ,\langle\psi_\theta,\sigma_x\psi_\theta\rangle =2\sqrt{p(1-p)}\cos\theta,

while the corresponding diagonal density operator gives zero. Enlarging the observable algebra changes which preparations can be distinguished. It does not merely change notation for the same restricted experiment.

This is why physical superselection discussions must identify available observables and reference systems. A statement that a phase is inaccessible within one model does not, without further argument, prove that no enlarged system or reference can reveal relational coherence. Giulini’s review discusses the conceptual status of such restrictions and distinguishes exact kinematical assumptions from dynamical explanations.

Sector-preserving dynamics and its domains

Section titled “Sector-preserving dynamics and its domains”

An autonomous dynamics preserves these sectors when its unitary group satisfies

U(t)Pα=PαU(t)for all t,α.U(t)P_\alpha=P_\alpha U(t) \quad\text{for all }t,\alpha.

For a self-adjoint generator, this means the sector subspaces reduce the Hamiltonian. In a diagonal sector representation H=⨁αHαH=\bigoplus_\alpha H_\alpha, its domain is

D(H)={ψ:ψα∈D(Hα),∑α∥Hαψα∥2<∞}.D(H)=\left\{\psi: \psi_\alpha\in D(H_\alpha), \sum_\alpha\|H_\alpha\psi_\alpha\|^2<\infty\right\}.

The square-summability condition is essential. Belonging componentwise to every sector domain does not alone make the full Hamiltonian action a Hilbert-space vector. Formal vanishing of a commutator on an unspecified test domain is likewise weaker than the displayed unitary commutation relation.

Finally, an approximate loss of off-diagonal entries through environmental decoherence does not establish an exact algebraic superselection rule. Nor does the elementary countable sum cover every sector construction: continuous decompositions require direct-integral theory, and general observable algebras can have more complicated representation structure.

Exercise: restriction can turn a pure state into a mixture

Section titled “Exercise: restriction can turn a pure state into a mixture”

For 0<p<10<p<1, write the restricted state of ψθ\psi_\theta as a convex combination of the two evaluation functionals on diagonal matrices. Show that these functionals are distinct.

Solution

Define ω0(diag⁡(a,b))=a\omega_0(\operatorname{diag}(a,b))=a and ω1(diag⁡(a,b))=b\omega_1(\operatorname{diag}(a,b))=b. Then ωψθ∣A=pω0+(1−p)ω1\omega_{\psi_\theta}|_{\mathcal A}=p\omega_0+(1-p)\omega_1. They are distinct because ω0(P0)=1\omega_0(P_0)=1 and ω1(P0)=0\omega_1(P_0)=0. Both weights are positive, so the restricted functional is not extreme. The full-space density operator PψθP_{\psi_\theta} remains rank one.