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Numerical Units and Dimensionless Variables

Nondimensionalization rewrites a quantum calculation in terms of explicit reference scales. It keeps numerical magnitudes manageable and reveals which parameter combinations control the physics. Setting ℏ=1\hbar=1 is meaningful only after specifying the corresponding time and energy units; it is not permission to mix frequencies, energies, and inverse seconds.

Required background. Array representations explains why wavefunction normalization carries a measure.

Choose a length ℓ>0\ell>0 and energy E∗>0E_*>0. With

x=ℓξ,t=ℏE∗τ,ψ(x,t)=ℓ−1/2ϕ(ξ,τ),x=\ell\xi,\qquad t=\frac{\hbar}{E_*}\tau, \qquad \psi(x,t)=\ell^{-1/2}\phi(\xi,\tau),

the one-dimensional equation becomes

i∂τϕ=[−α∂ξ2+v(ξ,τ)]ϕ,α=ℏ22mℓ2E∗,v=VE∗.i\partial_\tau\phi =\left[-\alpha\partial_\xi^2+v(\xi,\tau)\right]\phi, \qquad \alpha=\frac{\hbar^2}{2m\ell^2E_*}, \qquad v=\frac{V}{E_*}.

The factor ℓ−1/2\ell^{-1/2} follows by substituting dx=ℓ dξdx=\ell\,d\xi into the norm. In dd spatial dimensions it becomes ℓ−d/2\ell^{-d/2} for a single common length scale. Coordinate transformations with nonconstant Jacobians require the more general treatment in coordinate transformations.

One may choose E∗=ℏ2/(2mℓ2)E_*=\hbar^2/(2m\ell^2) so that α=1\alpha=1. That convention differs from oscillator units, where the kinetic coefficient is 1/21/2. Record the actual scaled equation instead of relying on a phrase such as “natural units.”

For V(x)=mω2x2/2+λx4V(x)=m\omega^2x^2/2+\lambda x^4, take

ℓ=ℏmω,E∗=ℏω.\ell=\sqrt{\frac{\hbar}{m\omega}}, \qquad E_*=\hbar\omega.

Then

Hℏω=−12∂ξ2+12ξ2+gξ4,g=λℏm2ω3.\frac{H}{\hbar\omega} =-\frac12\partial_\xi^2+\frac12\xi^2+g\xi^4, \qquad g=\frac{\lambda\hbar}{m^2\omega^3}.

At g=0g=0, the dimensionless energies are n+1/2n+1/2. Restoring units multiplies energies by ℏω\hbar\omega, lengths by ℓ\ell, and times by 1/ω1/\omega. A parameter sweep in gg therefore compares equivalent dimensionless Hamiltonians even when the dimensional masses and trap frequencies differ.

A grid spacing Δξ=0.02\Delta\xi=0.02 is a physical spacing 0.02ℓ0.02\ell. A box [−8,8][-8,8] means [−8ℓ,8ℓ][-8\ell,8\ell], not a universal length in meters. This distinction is essential when reusing a numerical benchmark for a different system.

An angular frequency Ω\Omega corresponds to energy ℏΩ\hbar\Omega; an ordinary frequency ff corresponds to hf=2πℏfhf=2\pi\hbar f. For a driven two-level Hamiltonian H=(ℏΩ/2)σxH=(\hbar\Omega/2)\sigma_x, dimensionless evolution uses (Ωℏ/E∗)σx/2(\Omega\hbar/E_*)\sigma_x/2. The factor of 1/21/2 belongs to the Hamiltonian convention, independently of the units.

A decay rate γ\gamma has units of inverse time. Its dimensionless value is γ~=γℏ/E∗\widetilde\gamma=\gamma\hbar/E_*. If a jump operator includes γ\sqrt\gamma, its coefficient scales with the square root of this rate. Scaling HH but leaving dissipative rates untouched changes their competition.

For the one-dimensional probability current,

j(x,t)=ℏmIm⁡(ψ∗∂xψ)=ℏmℓ2Im⁡(ϕ∗∂ξϕ).j(x,t)=\frac{\hbar}{m}\operatorname{Im}(\psi^*\partial_x\psi) =\frac{\hbar}{m\ell^2} \operatorname{Im}(\phi^*\partial_\xi\phi).

The density scales as ℓ−1\ell^{-1}, while current scales as inverse time. Check derived quantities individually rather than assuming every output scales like energy.

An eigenvalue residual r=Hc−Ecr=Hc-Ec has energy units for a normalized coefficient vector. A dimensionless residual uses r~=r/E∗\widetilde r=r/E_*. State whether an acceptance criterion is absolute, relative to ∥H∥\|H\|, or relative to a physically chosen energy scale. A tolerance of 10−1010^{-10} without units or normalization is incomplete.

Nondimensionalization does not by itself cure ill-conditioning. Multiplying an entire matrix by a scalar leaves its normwise condition number unchanged. It can prevent overflow and make tolerances interpretable; resolving disparate physical scales may still require adaptive meshes, suitable bases, or preconditioning.

Keep conversion at the input/output boundary where practical. Save ℓ,E∗\ell,E_* and all dimensionless couplings with the result. A second calculation in another consistent unit system should recover the same physical observable after conversion; this tests for missing ℏ\hbar, 2π2\pi, or mass factors.

Using E∗=ℏ2/(2mℓ2)E_*=\hbar^2/(2m\ell^2), find the dimensionless energies of an infinite well of width L=3ℓL=3\ell.

Solution

En=ℏ2π2n2/(2mL2)E_n=\hbar^2\pi^2n^2/(2mL^2) gives En/E∗=π2n2/9E_n/E_*=\pi^2n^2/9. The dimensionless interval has width three and the kinetic operator is −∂ξ2-\partial_\xi^2.

An energy splitting is quoted as E/h=5 GHzE/h=5\,\mathrm{GHz}. What angular frequency belongs in e−iEt/ℏe^{-iEt/\hbar}?

Solution

E/ℏ=2π×5×109 s−1E/\hbar=2\pi\times5\times10^9\,\mathrm{s}^{-1}. Inserting 5×1095\times10^9 directly would lengthen the phase period by a factor of 2π2\pi.

  • Higham, N. J., Accuracy and Stability of Numerical Algorithms, 2nd ed., SIAM, 2002, publisher edition — scaling and numerical error.
  • Tannor, D. J., Introduction to Quantum Mechanics: A Time-Dependent Perspective, University Science Books, 2007 — quantum propagation, physical scales, and oscillator conventions.