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First-Order Transition Probability

First-order time-dependent perturbation theory computes transition amplitudes produced by a weak time-dependent interaction. It is the entry point for resonance, absorption, emission, decay rates, and Fermi’s golden rule.

Split the Hamiltonian as

H(t)=H0+V(t),H(t)=H_0+V(t),

where H0H_0 is exactly solved:

H0∣n⟩=En∣n⟩.H_0\lvert n\rangle = E_n\lvert n\rangle.

We calculate transitions between distinct normalized states f≠if\ne i in an orthonormal eigenbasis of H0H_0. The perturbation VV includes its physical coupling strength; a “first-order probability” below means the square of a first-order amplitude, hence second order in that strength.

Required background. Interaction Picture fixes the phase convention, and Dyson Transition Amplitudes explains amplitude versus probability order.

In the interaction picture, the state obeys

iℏddt∣ψI(t)⟩=VI(t)∣ψI(t)⟩,i\hbar\frac{d}{dt}\lvert\psi_I(t)\rangle = V_I(t)\lvert\psi_I(t)\rangle,

where

VI(t)=eiH0(t−t0)/ℏV(t)e−iH0(t−t0)/ℏ.V_I(t) = e^{iH_0(t-t_0)/\hbar} V(t) e^{-iH_0(t-t_0)/\hbar}.

The first-order Dyson expansion gives

∣ψI(t)⟩≈[I−iℏ∫t0tdt′ VI(t′)]∣i⟩.\lvert\psi_I(t)\rangle \approx \left[ I-\frac{i}{\hbar} \int_{t_0}^{t}dt'\,V_I(t') \right] \lvert i\rangle.

Thus the first-order transition amplitude is

cf(1)(t)=−iℏ∫t0tdt′ ⟨f∣VI(t′)∣i⟩.c_f^{(1)}(t) = -\frac{i}{\hbar} \int_{t_0}^{t}dt'\, \langle f|V_I(t')|i\rangle.

For f=if=i, this is only a correction to the zeroth-order survival amplitude 11; squaring the correction alone does not give survival probability.

If V(t)V(t) is written in the Schrödinger picture and ∣i⟩,∣f⟩\lvert i\rangle,\lvert f\rangle are eigenstates of H0H_0, then

⟨f∣VI(t)∣i⟩=eiωfi(t−t0)⟨f∣V(t)∣i⟩,\langle f|V_I(t)|i\rangle = e^{i\omega_{fi}(t-t_0)} \langle f|V(t)|i\rangle,

with

ωfi=Ef−Eiℏ.\omega_{fi} = \frac{E_f-E_i}{\hbar}.

The transition amplitude is therefore a time integral of the perturbation matrix element multiplied by a phase. Transitions are enhanced when the time dependence of V(t)V(t) compensates this phase.

Constant Perturbation Switched On for a Finite Time

Section titled “Constant Perturbation Switched On for a Finite Time”

As a diagnostic example, suppose V(t)=VV(t)=V is constant from 00 to TT and zero outside that interval. Then

cf(1)(T)=−iℏVfi∫0Tdt eiωfit.c_f^{(1)}(T) = -\frac{i}{\hbar}V_{fi} \int_0^Tdt\,e^{i\omega_{fi}t}.

The integral gives

cf(1)(T)=−iℏVfi eiωfiT/22sin⁡(ωfiT/2)ωfi.c_f^{(1)}(T) = -\frac{i}{\hbar}V_{fi}\, e^{i\omega_{fi}T/2} \frac{2\sin(\omega_{fi}T/2)}{\omega_{fi}}.

The leading transition probability is

Pi→f(1)(T)=4∣Vfi∣2ℏ2sin⁡2(ωfiT/2)ωfi2.P_{i\to f}^{(1)}(T) = \frac{4\lvert V_{fi}\rvert^2}{\hbar^2} \frac{\sin^2(\omega_{fi}T/2)} {\omega_{fi}^2}.

This expression has a peak near ωfi=0\omega_{fi}=0, whose width is of order 1/T1/T.

If the perturbation contains a harmonic factor such as

V(t)=We−iΩt+W†eiΩt,V(t)=W e^{-i\Omega t}+W^\dagger e^{i\Omega t},

then the amplitude contains phase factors like

ei(ωfi−Ω)tandei(ωfi+Ω)t.e^{i(\omega_{fi}-\Omega)t} \quad\text{and}\quad e^{i(\omega_{fi}+\Omega)t}.

The first term is resonant when

Ω≈ωfi.\Omega\approx\omega_{fi}.

This is the basic mechanism behind absorption and stimulated emission in weak-drive calculations.

The first-order probability is

Pi→f≈∣cf(1)(t)∣2.P_{i\to f} \approx \lvert c_f^{(1)}(t)\rvert^2.

This is a leading-order probability, not an all-time exact probability. A necessary depletion check is ∑f≠i∣cf(1)∣2≪1\sum_{f\ne i}\lvert c_f^{(1)}\rvert^2\ll1, with continuum integrals when needed. Small probabilities alone are not sufficient: accumulated energy-shift phases and higher-order paths must also be negligible for the observable and time interval being predicted.

For long times near resonance in a two-level system, first-order perturbation theory eventually fails because probability would otherwise grow beyond its allowed range. An isolated coherent pair then requires Rabi dynamics. A rate description additionally requires a continuum or a specified loss of coherence; it does not follow just from failure of first order.

For very short times, the amplitude is approximately linear in TT:

cf(1)(T)≈−iℏVfiT.c_f^{(1)}(T) \approx -\frac{i}{\hbar}V_{fi}T.

Thus the probability starts quadratically:

Pi→f(1)(T)≈∣Vfi∣2T2ℏ2.P_{i\to f}^{(1)}(T) \approx \frac{\lvert V_{fi}\rvert^2T^2}{\hbar^2}.

This short-time quadratic behavior is different from the linear-in-time behavior of a golden-rule rate, which emerges only after additional continuum and time-scale assumptions.

For a single discrete final state, the finite-time probability oscillates or grows only within the limits of perturbation theory. For a continuum of final states, the narrow sinc-squared peak can be integrated against a density of states. When the spectral weight is smooth over the finite-time peak and depletion remains small, this produces Fermi’s Golden Rule. The required interval is long compared with the reservoir correlation time but short compared with the depletion time.

The difference between a probability and a rate is therefore physical. It is not just notation.

At short times a constant perturbation connects the initial state to NN orthogonal states with equal matrix-element magnitude vv. Find the leading total transition probability. Why can checking one channel fail?

Solution

Each probability is v2T2/ℏ2v^2T^2/\hbar^2, so their sum is Nv2T2/ℏ2Nv^2T^2/\hbar^2. The necessary short-time criterion is N vT/ℏ≪1\sqrt N\,vT/\hbar\ll1. Completeness gives the general expression

∑f≠iPi→f(T)=T2ℏ2(⟨i∣V2∣i⟩−⟨i∣V∣i⟩2)+o(T2).\sum_{f\ne i}P_{i\to f}(T) =\frac{T^2}{\hbar^2} \left(\langle i|V^2|i\rangle-\langle i|V|i\rangle^2\right) +o(T^2).

This assumes ∣i⟩|i\rangle has finite variance of VV. Since ∣i⟩|i\rangle is an H0H_0 eigenstate, this is also the variance of the full constant Hamiltonian in the initial state. It agrees with the exact short-time survival expansion.

Take ωfi→0\omega_{fi}\to0 in the rectangular-pulse formula. At what time scale must the leading prediction for this channel cease to be reliable?

Solution

Using sin⁡x/x→1\sin x/x\to1 gives Pi→f≃∣Vfi∣2T2/ℏ2P_{i\to f}\simeq |V_{fi}|^2T^2/\hbar^2, with no divergence at fixed TT. At T∼ℏ/∣Vfi∣T\sim\hbar/|V_{fi}| depletion and repeated transitions matter. The exact two-state resonant result is sin⁡2(∣Vfi∣T/ℏ)\sin^2(|V_{fi}|T/\hbar) after subtracting the common diagonal energy.

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