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A threshold is an energy where the structure of propagating channels changes. Even when scattering is complete at positive energy, the resolvent may have a different expansion at a threshold. In three dimensions, zero energy already distinguishes a regular point, a nonnormalizable resonance, and a genuine eigenstate. These distinctions govern low-energy limits and can change late-time decay.

Required background. Stationary Scattering Theory explains why its positive-energy estimates exclude zero. Resonances distinguishes momentum and energy continuation. Scattering-length and effective-range formulas remain with Low-Energy Scattering.

A regular momentum expansion can be singular in energy

Section titled “A regular momentum expansion can be singular in energy”

For the free three-dimensional Hamiltonian H0=−ΔH_0=-\Delta, the localized outgoing resolvent has kernel

R0(k;x,y)=eik∣x−y∣4π∣x−y∣=14π∣x−y∣+ik4π+O(k2).\mathcal R_0(k;x,y) =\frac{e^{ik|x-y|}}{4\pi|x-y|} =\frac1{4\pi|x-y|}+\frac{ik}{4\pi}+O(k^2).

On fixed compact source and observation regions, this is an ordinary analytic expansion in kk near zero. In the energy variable z=k2z=k^2, however, the linear term is proportional to z\sqrt z. Thus a branch point in energy does not require a pole in momentum.

This distinction persists in more complicated channel problems. Near a channel threshold EjE_j, its momentum behaves like E−Ej\sqrt{E-E_j}, and the number or character of open channels changes. An expansion valid away from all thresholds need not be uniform as one is approached.

The three-dimensional formula is not universal. The one-dimensional free resolvent contains a 1/k1/k term, and two-dimensional expansions contain logarithms. Dimension and boundary conditions belong in the statement of every threshold classification.

Zero-energy resonance versus zero-energy eigenstate

Section titled “Zero-energy resonance versus zero-energy eigenstate”

For real bounded compactly supported VV on R3\mathbb R^3, consider distributional solutions of

(−Δ+V)ψ=0.(-\Delta+V)\psi=0.

A zero-energy eigenstate is a nonzero L2L^2 solution in the operator domain. A zero-energy resonance, in the convention used here, is a nonzero solution in Hloc2H^2_{\rm loc} satisfying

ψ∈L−s2for every s>1/2,ψ∉L2.\psi\in L^2_{-s}\quad\text{for every }s>1/2, \qquad \psi\notin L^2.

The weights are defined by ∥ψ∥L−s2=∥⟨x⟩−sψ∥2\|\psi\|_{L^2_{-s}}=\|\langle x\rangle^{-s}\psi\|_2. In this compact-support setting a resonant solution has a nonzero 1/r1/r leading tail. It is locally regular but its unweighted norm diverges.

If neither a zero eigenstate nor a zero resonance exists, the threshold is called regular. The free constant function is not a three-dimensional resonance in this definition: it fails the weight condition for 1/2<s≤3/21/2<s\leq3/2.

The classification is equivalent to analyzing the zero-energy obstruction in the local Lippmann–Schwinger operator. If that operator is invertible at zero, analytic inversion yields the regular localized expansion. A nontrivial kernel requires a separate finite-dimensional analysis and can produce negative powers of kk. This is why simply substituting zero into a positive-energy inverse is unsafe.

A square well exactly at a resonance threshold

Section titled “A square well exactly at a resonance threshold”

Let V(r)=−q2V(r)=-q^2 for r<Rr<R and zero for r>Rr>R, with q>0q>0 and ℏ=2m=1\hbar=2m=1. For an s-wave write ψ(r)=u(r)/r\psi(r)=u(r)/r. Regularity at the origin gives

u(r)=Asin⁡(qr),r<R.u(r)=A\sin(qr),\qquad r<R.

A zero-energy resonant exterior has u(r)=Bu(r)=B, so ψ(r)=B/r\psi(r)=B/r. Matching uu and u′u' at RR requires

B=Asin⁡(qR),qAcos⁡(qR)=0.B=A\sin(qR),\qquad qA\cos(qR)=0.

A nonzero resonant solution therefore occurs at qR=(n+12)πqR=(n+\tfrac12)\pi. In particular the first threshold occurs at qR=π/2qR=\pi/2.

Its tail is not square-integrable:

∫R∞∣ψ(r)∣2r2 dr=∣B∣2∫R∞dr=∞,\int_R^\infty |\psi(r)|^2r^2\,dr =|B|^2\int_R^\infty dr=\infty,

but adding the weight ⟨r⟩−2s\langle r\rangle^{-2s} makes it integrable for s>1/2s>1/2. The near-origin limit of sin⁡(qr)/r\sin(qr)/r is finite, so the divergence comes entirely from infinity.

This is the threshold test, not a second derivation of the full square-well scattering amplitude. The physical matching and cross sections are developed in Square-Well Scattering.

Threshold spectral weight produces power-law tails

Section titled “Threshold spectral weight produces power-law tails”

A simple exact spectral model demonstrates the time consequence without asserting a universal decay rate. Let a normalized state have energy density on E≥0E\geq0

ρ(E)=Eαe−E/ΛΓ(α+1)Λα+1,α>−1,Λ>0.\rho(E)= \frac{E^\alpha e^{-E/\Lambda}} {\Gamma(\alpha+1)\Lambda^{\alpha+1}}, \qquad \alpha>-1,\quad\Lambda>0.

Its survival amplitude is the elementary Laplace transform

A(t)=∫0∞e−itE/ℏρ(E) dE=(1+iΛt/ℏ)−α−1.A(t)=\int_0^\infty e^{-itE/\hbar}\rho(E)\,dE =(1+i\Lambda t/\hbar)^{-\alpha-1}.

Consequently ∣A(t)∣2=[1+(Λt/ℏ)2]−α−1|A(t)|^2=[1+(\Lambda t/\hbar)^2]^{-\alpha-1}. The threshold exponent determines the late-time power, while the high-energy exponential cutoff makes the model well-defined.

For a regular free three-dimensional packet with nonzero smooth Fourier amplitude at zero, the local spectral density behaves like E1/2E^{1/2}. Threshold obstructions can change such powers, but proving a decay statement for an interacting Hamiltonian requires precise weighted resolvent expansions and remainder estimates. The gamma-density model explains the mechanism; it is not a theorem assigning the same exponent to every potential or preparation.

  1. Why can a higher-angular-momentum zero-energy solution be an eigenstate rather than a resonance?
Solution

Its decaying exterior radial wavefunction behaves like r−ℓ−1r^{-\ell-1}. The norm tail is proportional to ∫R∞r−2ℓdr\int_R^\infty r^{-2\ell}dr, which converges for ℓ≥1\ell\geq1. If interior regularity and matching also hold, the resulting zero mode is square-integrable. The s-wave 1/r1/r tail fails this test.

  1. In the spectral model, compare amplitude and probability decay for α=1/2\alpha=1/2.
Solution

The amplitude magnitude decays as ∣t∣−3/2|t|^{-3/2} and the survival probability as ∣t∣−3|t|^{-3}. Confusing these exponents would also confuse a resonance amplitude width with a probability decay rate.

  • A. Jensen and T. Kato, “Spectral properties of Schrödinger operators and time-decay of the wave functions,” Duke Mathematical Journal 46, 583–611, 1979, doi:10.1215/S0012-7094-79-04631-3 — threshold spectral analysis and weighted decay.
  • A. Jensen and G. Nenciu, “A unified approach to resolvent expansions at thresholds,” Reviews in Mathematical Physics 13, 717–754, 2001; erratum 16, 675–677, 2004, doi:10.1142/S0129055X01000843, author preprint — dimension-dependent expansions and threshold obstructions.
  • M. Zworski, “Mathematical study of scattering resonances,” Bulletin of Mathematical Sciences 7, 1–85, 2017, doi:10.1007/s13373-017-0099-4, author text.