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A bounce is a finite-action Euclidean solution that leaves a metastable minimum, reaches a turning point beyond the barrier, and returns to the same minimum. It is the canonical saddle for the exponentially small decay of a metastable state.

For a background-subtracted potential U(x)U(x), the bounce satisfies

mxB′′=U′(xB),mx_B'' = U'(x_B),

with

xB(τ)→xF,τ→±∞.\begin{gathered} x_B(\tau)\to x_F, \\ \tau\to\pm\infty. \end{gathered}

Here xFx_F denotes the false minimum. Unlike an instanton between degenerate minima, a bounce makes a round trip and has one negative fluctuation mode in addition to its translation zero mode.

Required background. Euclidean time and action derives the continuation and background subtraction, instantons explains finite-action saddles, and barrier penetration provides the WKB comparison. False vacuum decay connects the saddle to a physical resonance and lifetime.

Consider a smooth one-dimensional potential with a local minimum at xFx_F. Shift its value so that

U(xF)=0.U(x_F)=0.

For a nondegenerate false minimum,

U′(xF)=0,U′′(xF)=mωF2>0.U'(x_F)=0, \qquad U''(x_F)=m\omega_F^2\gt0.

Suppose an escape direction contains a barrier top xbx_b and a point xtx_t beyond it such that

U′(xb)=0,U′′(xb)<0,Ub≡U(xb)>0,U(xt)=0,U(x)>0forxF<x<xt.\begin{gathered} U'(x_b)=0, \qquad U''(x_b)\lt0, \\ U_b\equiv U(x_b)\gt0, \\ U(x_t)=0, \\ U(x)\gt0 \quad \text{for} \quad x_F\lt x\lt x_t. \end{gathered}

Take xtx_t to be a simple root, U′(xt)<0U'(x_t)<0. It is the zero-energy turning point on the far side of the barrier, reached in finite Euclidean time. If it were instead another degenerate minimum, the trajectory would approach it only asymptotically and would describe an instanton, not the finite-center bounce considered here.

A metastable cubic potential with a false minimum, barrier top, and escape turning point beside the corresponding localized Euclidean bounce profile.

The false minimum xFx_F is separated from the escape region by a barrier. In Euclidean time the bounce approaches xFx_F at both ends, reaches xtx_t at its center τ0\tau_0, and returns. The cubic example below has an exact sech⁡2\operatorname{sech}^2 profile.

What the false vacuum means in zero spatial dimensions

Section titled “What the false vacuum means in zero spatial dimensions”

In field theory, “vacuum” denotes a state associated with a homogeneous field configuration. In ordinary quantum mechanics, the corresponding object is a wavepacket or resonance localized near a metastable well. The terminology is useful, but the local minimum itself is not an exact stationary quantum state.

Two common realizations must be distinguished:

  1. An open escape problem: the potential falls toward an unbounded or asymptotic region, and outgoing boundary conditions define a resonance with a complex energy.
  2. A closed multiwell problem: the full Hamiltonian has a real discrete spectrum, but a state initially localized in one well can remain trapped for a long time before tunneling, dephasing, and eventually recurring.

A local minimum alone does not guarantee a useful exponential decay regime. The barrier must produce a parametrically long timescale, normally requiring a bounce action BB with

Bℏ≫1.\frac{B}{\hbar}\gg1.

Subtract the false-minimum background and define

B[x]=∫−∞∞dτ[m2(x′)2+U(x)].B[x] = \int_{-\infty}^{\infty} d\tau \left[ \frac{m}{2}(x')^2 + U(x) \right].

Stationarity gives

mx′′=U′(x).mx'' = U'(x).

The bounce boundary conditions are

xB(τ)→xF,xB′(τ)→0,τ→±∞,xB(τ0)=xt,xB′(τ0)=0.\begin{gathered} x_B(\tau)\to x_F, \qquad x_B'(\tau)\to0, \\ \tau\to\pm\infty, \\ x_B(\tau_0)=x_t, \qquad x_B'(\tau_0)=0. \end{gathered}

The solution is symmetric about its center:

xB(τ0+σ)=xB(τ0−σ).x_B(\tau_0+\sigma) = x_B(\tau_0-\sigma).

Translation invariance makes τ0\tau_0 arbitrary. This continuous family of equal-action solutions is the origin of the translation zero mode.

The Euclidean equation can be written

mxB′′=−ddxB[−U(xB)].mx_B'' = - \frac{d}{dx_B} \left[ -U(x_B) \right].

In the mechanical analogy, a particle starts asymptotically at the unstable equilibrium on top of −U-U at xFx_F, rolls to xtx_t, stops there, and retraces its path. It takes infinite Euclidean time to leave or return to the top because xFx_F is approached exponentially.

The analogy constructs a stationary path. It does not describe the real-time motion of the quantum particle during tunneling.

Because the Euclidean Lagrangian has no explicit τ\tau dependence,

EE=m2(xB′)2−U(xB)\mathcal E_E = \frac{m}{2}(x_B')^2 - U(x_B)

is conserved. The asymptotic boundary conditions set EE=0\mathcal E_E=0, so

m2(xB′)2=U(xB).\frac{m}{2}(x_B')^2 = U(x_B).

On either half of the bounce,

∣dxBdτ∣=2U(xB)m.\left| \frac{dx_B}{d\tau} \right| = \sqrt{ \frac{2U(x_B)}{m} }.

The implicit profile is therefore

∣τ−τ0∣=m2∫xB(τ)xtdyU(y).\left| \tau-\tau_0 \right| = \sqrt{\frac{m}{2}} \int_{x_B(\tau)}^{x_t} \frac{dy}{\sqrt{U(y)}}.

Near xFx_F,

U(x)=mωF22(x−xF)2+O((x−xF)3),U(x) = \frac{m\omega_F^2}{2} (x-x_F)^2 + O\left( (x-x_F)^3 \right),

so the integral diverges logarithmically and

xB(τ)−xF∝e−ωF∣τ−τ0∣.x_B(\tau)-x_F \propto e^{-\omega_F|\tau-\tau_0|}.

The zero-energy first integral reduces the action:

B=∫−∞∞dτ[m2(xB′)2+U(xB)]=∫−∞∞dτ 2U(xB).\begin{aligned} B &= \int_{-\infty}^{\infty} d\tau \left[ \frac{m}{2}(x_B')^2 + U(x_B) \right] \\ &= \int_{-\infty}^{\infty} d\tau\, 2U(x_B). \end{aligned}

The outward and return branches contribute equally. Hence

B=2∫xFxtdx 2mU(x).B = 2 \int_{x_F}^{x_t} dx\, \sqrt{2mU(x)}.

The factor of two is structural. A monotone instanton crosses once between degenerate minima; a bounce leaves and returns to the same minimum.

For a one-dimensional barrier, define the fixed-energy WKB action

W(E)=∫x1(E)x2(E)dx 2m[U(x)−E].W(E) = \int_{x_1(E)}^{x_2(E)} dx\, \sqrt{2m[U(x)-E]}.

At the classical false-minimum energy E=0E=0,

B=2W(0).B = 2W(0).

Therefore the bounce factor

e−B/ℏe^{-B/\hbar}

matches the leading WKB probability suppression e−2W/ℏe^{-2W/\hbar}. A WKB wavefunction amplitude contains only e−W/ℏe^{-W/\hbar}.

The false-well ground energy is actually of order ℏωF/2\hbar\omega_F/2, not exactly zero. Using W(EF)W(E_F) shifts some subleading terms between exponent and prefactor. Agreement claims must state the approximation order and energy convention.

Worked Example: Cubic Metastable Potential

Section titled “Worked Example: Cubic Metastable Potential”

Consider

U(x)=mω22x2−g3x3,g>0.U(x) = \frac{m\omega^2}{2}x^2 - \frac{g}{3}x^3, \qquad g\gt0.

The cubic potential is a local escape model, unbounded below at large positive xx; a globally lower-bounded model can join it smoothly to an escape continuum beyond xtx_t without changing this classical bounce. The resonance problem still requires an outgoing boundary prescription. The false minimum is at xF=0x_F=0. The barrier top satisfies

xb=mω2g,x_b = \frac{m\omega^2}{g},

with height

Ub=m3ω66g2.U_b = \frac{m^3\omega^6}{6g^2}.

The nonzero root of U(x)=0U(x)=0 is

xt=3mω22g.x_t = \frac{3m\omega^2}{2g}.

The zero-energy equation is

(xB′)2=ω2xB2(1−xBxt).(x_B')^2 = \omega^2x_B^2 \left( 1-\frac{x_B}{x_t} \right).

The solution centered at τ0\tau_0 is

xB(τ)=xtsech⁡2[ω2(τ−τ0)].x_B(\tau) = x_t \operatorname{sech}^2 \left[ \frac{\omega}{2} (\tau-\tau_0) \right].

Indeed,

xB′=−ωxBtanh⁡[ω2(τ−τ0)],1−xBxt=tanh⁡2[ω2(τ−τ0)],\begin{aligned} x_B' &= - \omega x_B \tanh \left[ \frac{\omega}{2} (\tau-\tau_0) \right], \\ 1-\frac{x_B}{x_t} &= \tanh^2 \left[ \frac{\omega}{2} (\tau-\tau_0) \right], \end{aligned}

so the first integral is satisfied on both branches.

Using the round-trip formula,

B=2mω∫0xtdx x1−xxt=815mωxt2=6m3ω55g2.\begin{aligned} B &= 2m\omega \int_0^{x_t} dx\, x \sqrt{ 1-\frac{x}{x_t} } \\ &= \frac{8}{15} m\omega x_t^2 \\ &= \frac{6m^3\omega^5}{5g^2}. \end{aligned}

In terms of the barrier height,

B=365Ubω.B = \frac{36}{5} \frac{U_b}{\omega}.

The natural dimensionless coupling is

λ≡ℏg2m3ω5,\lambda \equiv \frac{\hbar g^2} {m^3\omega^5},

for which

Bℏ=65λ.\frac{B}{\hbar} = \frac{6}{5\lambda}.

The bounce expansion is controlled when λ≪1\lambda\ll1.

Write

x(τ)=xB(τ)+η(τ).x(\tau) = x_B(\tau) + \eta(\tau).

The quadratic fluctuation operator is

MB=−md2dτ2+U′′(xB).\mathcal M_B = - m\frac{d^2}{d\tau^2} + U''(x_B).

Differentiate the bounce equation with respect to τ\tau:

mxB′′′=U′′(xB)xB′.m x_B''' = U''(x_B)x_B'.

Therefore

MBxB′=0.\mathcal M_B x_B' = 0.

The zero mode shifts the center τ0\tau_0. It must be removed from the ordinary determinant and replaced by an integral over τ0\tau_0.

The zero mode xB′x_B' changes sign once, at the center of the bounce. For a one-dimensional Sturm–Liouville operator on the Euclidean line, eigenfunctions are ordered by their number of nodes. A normalizable zero eigenfunction with one node has one lower eigenfunction with no nodes. Its eigenvalue is negative.

Thus a simple one-dimensional bounce has exactly one negative mode. This statement assumes the usual isolated bounce and self-adjoint fluctuation problem. Additional negative modes can signal a different saddle, an excited or oscillating solution, or an incorrectly chosen decay configuration.

For the cubic example,

MBm=−d2dτ2+ω2×[1−3sech⁡2(ω2(τ−τ0))].\frac{\mathcal M_B}{m} = - \frac{d^2}{d\tau^2} + \omega^2 \times \left[ 1 - 3\operatorname{sech}^2 \left( \frac{\omega}{2} (\tau-\tau_0) \right) \right].

With

z=ω2(τ−τ0),z = \frac{\omega}{2} (\tau-\tau_0),

this becomes the Pöschl–Teller operator

MB=mω24[−d2dz2+4−12sech⁡2z].\mathcal M_B = \frac{m\omega^2}{4} \left[ - \frac{d^2}{dz^2} + 4 - 12\operatorname{sech}^2z \right].

Its negative and zero modes can be displayed explicitly:

modeeigenvalueη−(z)∝sech⁡3z−5mω2/4η0(z)∝sech⁡2z tanh⁡z0\begin{array}{c|c} \text{mode} & \text{eigenvalue} \\ \hline \eta_-(z)\propto\operatorname{sech}^3z & -5m\omega^2/4 \\ \eta_0(z)\propto \operatorname{sech}^2z\,\tanh z & 0 \end{array}

The zero mode is proportional to xB′x_B'. The remaining discrete positive mode and continuum affect the determinant prefactor but not the classical exponent.

For a long Euclidean interval of duration TT, the arbitrary center produces a factor proportional to TT. Widely separated bounces can then be summed in a dilute approximation. The negative direction requires a contour prescription inherited from the metastable boundary problem. Its prescribed continuation produces an imaginary contribution to the false-well resonance energy; the mode alone does not select that prescription.

The resulting semiclassical structure is

Eres=EF−iℏΓ2,E_{\mathrm{res}} = \mathcal E_F - \frac{i\hbar\Gamma}{2},

with

Γ∼Ae−B/ℏ[1+O(ℏB)].\Gamma \sim A e^{-B/\hbar} \left[ 1 + O\left( \frac{\hbar}{B} \right) \right].

The exponent is fixed by the classical bounce. The prefactor AA must have units of inverse time and depends on fluctuation determinants, zero-mode normalization, the negative-mode contour, and the definition of the metastable state.

This formula does not assert exact exponential decay at all times. Unitary quantum mechanics gives nonexponential behavior at sufficiently short and long times. The bounce result describes the resonance-dominated regime in which a decay rate is a useful emergent quantity.

A one-bounce calculation is parametrically credible when:

Bℏ≫1,ΓωF≪1.\frac{B}{\hbar}\gg1, \qquad \frac{\Gamma}{\omega_F}\ll1.

The first condition suppresses each event. For the cubic example the bounce width is of order 1/ωF1/\omega_F, and the second condition also controls dilution. For a more general potential with a broad core, use its actual Euclidean width τB\tau_B and require the magnitude of the event density times τB\tau_B to be small. Repeated bounces here are terms in a Euclidean persistence amplitude, not repeated real-time escapes of the same particle.

The symbolic form Ae−B/ℏA e^{-B/\hbar} hides several logically distinct operations.

Ingredient Why it matters
Reference determinant Normalizes fluctuations relative to the false-well saddle
Translation zero mode Replaces a vanishing determinant eigenvalue by an integral over τ0\tau_0
One negative mode Requires a contour prescription to obtain the imaginary part associated with decay
Boundary conditions Distinguish a resonance, fixed-endpoint kernel, thermal trace, and closed system
State normalization Fixes whether the answer is a kernel coefficient, energy width, or rate
Multi-bounce sum Converts the one-event contribution into long-time extensive behavior

The familiar schematic zero-mode replacement,

(det⁡MB)−1/2⟶J0∫dτ0×(det⁡′MB)−1/2.(\det\mathcal M_B)^{-1/2} \longrightarrow J_0 \int d\tau_0 \times (\det{}'\mathcal M_B)^{-1/2}.

contains a Jacobian J0J_0 whose precise form depends on the path-integral measure and normalization convention. The negative Gaussian direction is not convergent on the original real fluctuation contour; its continuation supplies an imaginary factor and a prescription-dependent half factor.

These details cannot be reconstructed from BB alone. Fluctuation Determinants Preview explains the determinant ratio and collective-coordinate normalization.

For a general one-dimensional potential, the first integral is usually more stable than direct shooting.

  1. Find xFx_F, the barrier top, and the first root xtx_t beyond the barrier with U(xt)=U(xF)U(x_t)=U(x_F).
  2. Shift U(xF)U(x_F) to zero.
  3. Evaluate
B=2∫xFxtdx 2mU(x).B = 2 \int_{x_F}^{x_t} dx\, \sqrt{2mU(x)}.
  1. Reconstruct the profile from
∣τ−τ0∣=m2∫xB(τ)xtdyU(y).\left| \tau-\tau_0 \right| = \sqrt{\frac{m}{2}} \int_{x_B(\tau)}^{x_t} \frac{dy}{\sqrt{U(y)}}.

The integrable square-root behavior at xtx_t and logarithmic divergence at xFx_F should be handled with endpoint-aware quadrature or a change of variables.

On a finite symmetric interval [−L,L][-L,L], impose

xB′(0)=0,xB(L)≈xF,x_B'(0)=0, \qquad x_B(L)\approx x_F,

and solve only on [0,L][0,L]. The center value approaches xtx_t as L→∞L\to\infty. A boundary-value solver is usually more stable than launching exactly from xtx_t with zero velocity, because the latter is sensitive to roundoff.

A converged solution should satisfy:

  • EE=m(xB′)2/2−U(xB)≈0\mathcal E_E=m(x_B')^2/2-U(x_B)\approx0 along the path;
  • direct τ\tau integration and configuration-space quadrature agree for BB;
  • the endpoint error falls as e−ωFLe^{-\omega_F L};
  • the smallest odd fluctuation eigenvalue approaches zero as the interval grows and the grid is independently refined;
  • exactly one lower eigenvalue remains negative;
  • BB is stable under independent changes of LL, mesh density, and quadrature rule.

The translation mode is an especially sensitive end-to-end check because it tests the profile, derivatives, fluctuation operator, and boundary truncation at once.

Several real bounces can exist when a potential has multiple escape directions or intermediate wells. At leading exponential order, the smallest admissible action dominates:

Bdom=min⁡αBα,B_{\mathrm{dom}} = \min_\alpha B_\alpha,

provided no symmetry, contour, or boundary condition excludes that saddle. Nearly equal actions require prefactors and channel information. Distinct orthogonal outgoing channels contribute additive rates; interference is relevant only when alternatives feed the same coherent final amplitude.

Other possibilities include:

  • periodic bounces at finite temperature;
  • energy-dependent periodic instantons;
  • multidimensional bounces with more than one path through configuration space;
  • complex saddles when no relevant real Euclidean solution exists;
  • oscillating solutions with extra negative modes.

Not every stationary Euclidean solution controls a decay rate. Boundary data, contour accessibility, and fluctuation signature remain part of the selection rule.

For one scalar field in dd spatial dimensions,

SE[ϕ]=∫dτ ddx×[12(∂τϕ)2+12(∇ϕ)2+V(ϕ)].S_E[\phi] = \int d\tau\,d^d x \times \left[ \frac12(\partial_\tau\phi)^2 + \frac12(\boldsymbol\nabla\phi)^2 + V(\phi) \right].

Under the standard assumptions for a single scalar, the least-action bounce can be taken to be rotationally symmetric in D=d+1D=d+1 Euclidean dimensions. With

ρ=τ2+∣x∣2,\rho = \sqrt{ \tau^2+|\mathbf x|^2 },

the radial equation is

d2ϕBdρ2+dρdϕBdρ=V′(ϕB),\frac{d^2\phi_B}{d\rho^2} + \frac{d}{\rho} \frac{d\phi_B}{d\rho} = V'(\phi_B),

with

ϕB′(0)=0,ϕB(ρ)→ϕFasρ→∞.\begin{gathered} \phi_B'(0)=0, \\ \phi_B(\rho)\to\phi_F \quad \text{as} \quad \rho\to\infty. \end{gathered}

The term dϕB′/ρd\phi_B'/\rho acts like friction in the inverted-potential analogy. The mechanical energy obeys

ddρ[12(ϕB′)2−V(ϕB)]=−dρ(ϕB′)2≤0.\frac{d}{d\rho} \left[ \frac12(\phi_B')^2 - V(\phi_B) \right] = - \frac{d}{\rho} (\phi_B')^2 \leq0.

Quantum mechanics is the case d=0d=0, where the friction term vanishes and the exact first integral is recovered. In field theory the center value is not generally the equal-potential turning point; it must be tuned so that friction leaves the solution at ϕF\phi_F as ρ→∞\rho\to\infty. This is the basis of the overshoot–undershoot construction.

The field-theory exponent is

B=SE[ϕB]−SE[ϕF].B = S_E[\phi_B] - S_E[\phi_F].

Gauge fields, fermions, renormalization, multiple scalar fields, gravity, and finite temperature add substantial structure. Bridge to QFT Instantons maps the saddle dictionary, while From Euclidean Time to Euclidean QFT explains Euclidean fields and reconstruction.

1. Distinguish a simple turning point from a second minimum

Section titled “1. Distinguish a simple turning point from a second minimum”

Compare the time integral near xtx_t when U(x)≃c(xt−x)U(x)\simeq c(x_t-x) with c>0c>0, and when U(x)≃mΩ2(xt−x)2/2U(x)\simeq m\Omega^2(x_t-x)^2/2.

Solution

The Euclidean time integral is proportional to ∫dx/U(x)\int dx/\sqrt{U(x)}. At a simple root it behaves as ∫dy/y\int dy/\sqrt y, which is finite. At a quadratic minimum it behaves as ∫dy/y\int dy/y, which diverges logarithmically. The first case permits a bounce to turn at finite center time; the second gives an asymptotic approach to another vacuum.

Suppose the tail is

xB(τ)−xF≃Ce−ωF∣τ∣.x_B(\tau)-x_F \simeq C e^{-\omega_F|\tau|}.

Estimate the action omitted by truncating the Euclidean line to [−L,L][-L,L].

Solution

In the quadratic tail,

U≃mωF22(xB−xF)2,U \simeq \frac{m\omega_F^2}{2} (x_B-x_F)^2,

and the zero-energy relation makes the kinetic term equal to UU. On the positive tail,

δB+≃∫L∞dτ mωF2C2e−2ωFτ=mωFC22e−2ωFL.\begin{aligned} \delta B_+ &\simeq \int_L^\infty d\tau\, m\omega_F^2C^2 e^{-2\omega_F\tau} \\ &= \frac{m\omega_F C^2}{2} e^{-2\omega_F L}. \end{aligned}

The negative tail contributes equally, so

δB≃mωFC2e−2ωFL.\delta B \simeq m\omega_F C^2 e^{-2\omega_F L}.

The endpoint displacement is of order e−ωFLe^{-\omega_F L}, while the action error is of order e−2ωFLe^{-2\omega_F L}.

3. Find the positive bound fluctuation mode

Section titled “3. Find the positive bound fluctuation mode”

The cubic bounce has a dimensionless fluctuation operator −d2/dz2+4−12sech⁡2z-d^2/dz^2+4-12\operatorname{sech}^2z. Besides the negative and zero modes, verify the positive bound mode proportional to sech⁡z [5tanh⁡2z−1]\operatorname{sech}z\,[5\tanh^2z-1] and identify the continuum threshold.

Solution

Direct differentiation gives dimensionless eigenvalue 33, or 3mω2/43m\omega^2/4 for MB\mathcal M_B. The eigenfunction has two nodes, consistent with its position above the nodeless negative mode and one-node zero mode. At ∣z∣→∞|z|\to\infty the potential tends to 44, so the continuum starts at mω2m\omega^2. The threshold solution is not an additional square-integrable bound state.

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